Answer: a) 
Step-by-step explanation:
We know that the volume of an oblique pyramid is given by :-
If the volume of an oblique pyramid with a square base is V units³ and the height is h units.
Then, we have
Multiply 3 on both sides , we get
Divide both sides by h , we get
i.e. 
Hence, the expression represents the area of the base of the pyramid =
Hence, the correct answer is a) 3 v/h units^2
Answer:
yes i took this test thats correct ! brainliest please :)
Step-by-step explanation:
Answer: 5
Step-by-step explanation:
2x + 3 = 13
Check the picture below.
so the area of the hexagon is really just the area of two isosceles trapezoids.
![\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ a=2\\ b=4\\ h=2 \end{cases}\implies \begin{array}{llll} A=\cfrac{2(2+4)}{2}\implies A=6 \\\\\\ \stackrel{\textit{twice that much}}{2A = 12} \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20h%3Dheight%5C%5C%20a%2Cb%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D2%5C%5C%20b%3D4%5C%5C%20h%3D2%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20A%3D%5Ccfrac%7B2%282%2B4%29%7D%7B2%7D%5Cimplies%20A%3D6%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Btwice%20that%20much%7D%7D%7B2A%20%3D%2012%7D%20%5Cend%7Barray%7D)
Answer:
sin θ = 15/17
Step-by-step explanation:
First we have to know how much the hypotenuse measures.
to take out the hypotenuse we will use pitagoras, with the following formula.
h^2 = c1^2 + c2^2
c1 = 8
c2 = 15
h^2 = 8^2 + 15^2
h^2 = 64 + 225
h = √ 289
h = 17
well to start we have to know the relationships between angles, legs and the hypotenuse.
a: adjacent
o: opposite
h: hypotenuse
sin θ = o/h
cos θ= a/h
tan θ = o/a
we want to know the sin of θ
sin θ = o/h
sin θ = 15/17
