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densk [106]
3 years ago
15

HELP FAST 100 POINTS 100 POINTS What is the value of the expression when a = 5, b = 4 , and c = 6?⁢ 4a2b−c 2 5 9 10

Mathematics
2 answers:
nalin [4]3 years ago
6 0

Answer:

394

Step-by-step explanation:

<u>Step 1:  Set a to 5, b to 4, and c to 6</u>

4a^2b-c

4(5)^2(4)-(6)

4(25)(4)-6

400 - 6

394

Answer:  394

ohaa [14]3 years ago
3 0

For this case we must find the value of the following expression:

4a ^ 2b-c

When:

a = 5\\b = 4\\c = 6

Substituting the given values we have:

4 (5) ^ 2 * 4-6 =\\4 (25) (4) -6=\\400-6 =\\394

Finally, the value of the expression is 394.

Answer:

The value of the expression is 394.

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Lines a and b are parallel. Line c is a transversal. Find the measures of all angles formed by a,b, and c, if:
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Answer:

150º and 30º angles.

Step-by-step explanation:

When you have parallel lines that are vut by a transversal line, you get a 2 pairs of 4 angles, this pairs are congruent or suplementary, this means that the sum of their angles is 180º or they are equal. So ig you have that one angle is 150º the other one since is suplementary must be 30º, since 150*30=180, and all of the angles are equal to these two, 150º and 30º angles.

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Calculate the average rate of change over the interval 2
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Answer:

Average rate of change over the interval 2<= x <= 5:

y = 3x + 5:        3

y = 3x^2 + 1:     21

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<u />

Step-by-step explanation:

2<= x <= 5

Average rate of change over the interval 2<= x <= 5:

<u>y = 3x + 5</u>

y(5) = 3(5) + 5 = 20

y(2) = 3(2) + 5 = 11

Average rate of change = (20 - 11)/(5-2) = 9/3 = <u>3</u>

<u />

<u>y = 3x^2 + 1</u>

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y(2) = 3(2^2) + 1= 13

Average rate of change = (76 - 13)/(5-2) = 63/3 = <u>21</u>

<u />

<u>y = 3^x</u>

y(5) = 3^5 = 243

y(2) = 3^2 =9

Average rate of change = (243-9)/(5-2) = 234/3 =<u> 78</u>

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