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fomenos
3 years ago
7

Combine and simplify the following radical expression.

Mathematics
2 answers:
guajiro [1.7K]3 years ago
3 0

Answer:

<h2>24 \sqrt{5}</h2>

Step-by-step explanation:

2 \sqrt{20}  + 8 \sqrt{45}  -  \sqrt{80}

= 2 \sqrt{2 \times 2 \times 5}   + 8 \sqrt{3 \times 3 \times 5}  -  \sqrt{2 \times 2 \times 2 \times 2 \times 5}

= 2(2 \sqrt{5} ) + 8(3 \sqrt{5} ) - (4 \sqrt{5} )

= 4 \sqrt{5}  + 24 \sqrt{5}  - 4 \sqrt{5}

= 24 \sqrt{5} (ans)

drek231 [11]3 years ago
3 0

Answer:

\huge\boxed{24\sqrt5}

Step-by-step explanation:

2\sqrt{20}+8\sqrt{45}-\sqrt{80}\\\\=2\sqrt{4\cdot5}+8\sqrt{9\cdot5}-\sqrt{16\cdot5}\\\\\text{use}\ \sqrt{a\cdot b}=\sqrt{a}\cdot\sqrt{b}\\\\=2\sqrt4\cdot\sqrt5+8\sqrt9\cdot\sqrt5-\sqrt{16}\cdot\sqrt5\\\\\text{we know}\ a\sqrt{b}=a\cdot\sqrt{b},\ \text{and}\ \sqrt{a}=b\iff b^2=a\\\\\text{Therefore}\\ 2\sqrt{4}=2\cdot\sqrt4=2\cdot2=4\\8\sqrt9=8\cdot\sqrt9=8\cdot3=24\\\sqrt{16}\cdot\sqrt5=4\cdot\sqrt5=4\sqrt5\\\\\text{Therefore}

=2\sqrt4\cdot\sqrt5+8\sqrt9\cdot\sqrt5-\sqrt{16}\cdot\sqrt5=4\sqrt5+24\sqrt5-4\sqrt5\\\\=(4+24-4)\sqrt5=24\sqrt5

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