Cual es la amplitud de estos conjuntos de datos 12,16,48,64,36,48,12,32,y 48

What does 20% of 35 equal? Answer

Sholpan [36]

I thinks believe it's 7

8 0

3 years ago

Read 2 more answers

Which rules of exponents will be used to evaluate the expression. Check all that apply

julia-pushkina [17]

Hello!

The answer are:

- Product of powers.

- Power of a power.

- Negative exponents.

Let's solve it!

It's a math rule that we must solve first what's into a brake or parenthesis, so,

First: Product of powers $[(7)^{5}*(7)^{3}]$

According to the exponent's law, we have a product of powers case, so, we need to sum the exponents and keep the base

Exponents: 5 and 3

Base: 7

Applying it we have:

$(7)^{5+3}$

$(7)^{8}$

Then,

We have a power of a power case, which involves multiplying the exponents:

$[(7)^{5}*(7)^{3}]^{-4}$

Exponents: 3 and -4

Then,

$(7)^{8*-4}$

Finally, we can apply the negative exponents, the negative exponent's rules state that negative exponents are the reciprocal of the positive exponents,

So, we will have that:

$(7)^{-32}=\frac{1}{7^{32} }$

Have a nice day!

6 0

3 years ago

Read 2 more answers

Write the expression nine divided by the quantity of x plus y

seropon [69]

9514 1404 393

Answer:

$\text{A)}\quad\dfrac{9}{x+y}$

Step-by-step explanation:

In the English expression, you need to understand that "A divided by B" means that A is the numerator and B is the denominator of the fraction representing the division. Here, "B" is "the quantity of ...", which means that the stuff after "of ..." is to be treated as a single item, the denominator in this case. That item is "x plus y." So, the expression in math terms is ...

$\dfrac{9}{x+y}$

When this is written in plain text, the "quantity" is put in parentheses, because the fraction bar no longer serves as a grouping symbol:

9/(x+y)

These expressions match the first choice, A.

7 0

3 years ago

Can someone help me with this question? I’ll mark you brainliest!!!

Mariulka [41]

Answer:

A. P' = (9, -2)

B. P" = (1, -4)

Step-by-step explanation:

To make it easier to understand, make point C the origin (0 , 0). From that, you will notice point P is 3 units right and 5 units up of point C, meaning the coordinates of point P is (3, 5). A 90° rotation clockwise on point P (3, 5) is (5, -3). Since point C is 4 units right and 1 unit up from the actual origin, we will add that to (5,-3); (5 + 4, -3 + 1) = (9, -2). Therefore, P' = (9, -2).

Knowing the coordinates of P' allows us to figure out the coordinates of P''. Once again, we'll make point C the origin, meaning P' would be at (5, -3). Like we did before, we will perform a 90° rotation clockwise of (5, -3) to get (-3, -5). Lastly, add back the appropriate amount of units to (-3, -5) to make point C the center of rotation in this example; (-3 + 4, -5 + 1) = (1, -4). Therefore, P" = (1, -4).

Please note that this is only my method of solving translations. Please consult more official sources if you want to learn more. Other than that, I hope this helps!

7 0

3 years ago

Please answer the questions

Naily [24]

Answer:

1/18

Step-by-step explanation:

$( {2}^{ - 3} \times {16}^{ \frac{1}{2} } ) \div ( {81}^{ \frac{3}{4} } \times {27}^{ - \frac{1}{3} } ) \\ \\ =( {2}^{ - 3} \times {2}^{ \frac{4 \times 1}{2} } ) \div ( {3}^{ \frac{4 \times 3}{4} } \times {3}^{ - \frac{3 \times 1}{3} } ) \\ \\=( {2}^{ - 3} \times {2}^{ 2} ) \div ( {3}^{ 3 } \times {3}^{ - 1 } ) \\ \\=( {2}^{ - 3 + 2} ) \div ( {3}^{ 3 - 1 } ) \\ \\ = {2}^{ - 1} \div {3}^{2} \\ \\ = \frac{1}{2} \times \frac{1}{9} \\ \\ = \frac{1}{18}$

5 0

3 years ago