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3 years ago

14

Solve for the value of the variable below

1 answer:

Hitman42 [59]3 years ago

3 0

The variable X is equal to 16

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Simplify the expression.

spayn [35]

Answer:

C. $\huge\frac{1}{3x {y}^{2} {z}^{4}}$

Step-by-step explanation:

$(9 {x}^{2} {y}^{4} {z}^{8} )^{ - \frac{1}{2} } \\ \\ = ( {3}^{2} {x}^{2} {y}^{4} {z}^{8} )^{ - \frac{1}{2} } \\ \\ = \frac{1}{( {3}^{2} {x}^{2} {y}^{4} {z}^{8} )^{ \frac{1}{2} }} \\ \\ = \frac{1}{(3x {y}^{2} {z}^{4})^{2 \times \frac{1}{2} } } \\ \\ = \frac{1}{3x {y}^{2} {z}^{4}} \\ \\ \red{ \bold{ \therefore \: (9 {x}^{2} {y}^{4} {z}^{8} )^{ - \frac{1}{2} } = \frac{1}{3x {y}^{2} {z}^{4}} }}\\$

7 0

4 years ago

Find the solution set of 5x<36 when x ∈ n

Margaret [11]

Answer:

5x<36

5x/5 < 36/5

x < 7.2

4 0

3 years ago

Read 2 more answers

For brainiest:):):):):):):)

exis [7]

I used 3.14 for pi to solve easier.

6. 6.28

7. 21.98

8. 94.2

6 0

3 years ago

Suppose that the mean water hardness of lakes in Kansas is 425 mg/L and these values tend to follow a normal distribution. A lim

tino4ka555 [31]

Answer:

The mean water hardness of lakes in Kansas is 425 mg/L or greater.

Step-by-step explanation:

We are given the following data set:

346, 496, 352, 378, 315, 420, 485, 446, 479, 422, 494, 289, 436, 516, 615, 491, 360, 385, 500, 558, 381, 303, 434, 562, 496

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{10959}{25} =438.36$

Sum of squares of differences = 175413.76

$S.D = \sqrt{\dfrac{175413.76}{24}} = 85.49$

Population mean, μ = 425 mg/L

Sample mean, $\bar{x}$ = 438.36

Sample size, n = 25

Alpha, α = 0.05

Sample standard deviation, s = 85.49

First, we design the null and the alternate hypothesis

$H_{0}: \mu \geq 425\text{ mg per Litre}\\H_A: \mu < 425\text{ mg per Litre}$

We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{438.36 - 425}{\frac{85.49}{\sqrt{25}} } = 0.7813$

Now, $t_{critical} \text{ at 0.05 level of significance, 24 degree of freedom } = -1.7108$

Since,

The calculated t-statistic is greater than the critical value, we fail to reject the null hypothesis and accept it.

Thus, the mean water hardness of lakes in Kansas is 425 mg/L or greater.

6 0

3 years ago

Victoria had the following car expenses last year:

Lyrx [107]

Answer: The answer is $0.42 APEX

7 0

3 years ago