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3 years ago

Question 4

Mathematics

2 answers:

Yuri [45]3 years ago

5 0

I’m not sure but I think it’s 1/2

djverab [1.8K]3 years ago

3 0

I’ll narrow it down for u it’s either 1/2 or 2 but don’t count me on it lol

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Please help !! ( Geometry )

avanturin [10]

Answer:

no sry

Step-by-step explanation:

4 0

2 years ago

What number is the same percent of 36 as 5 is of 24? If possible please show work:))

kiruha [24]

Answer:

7.4999999988

Step-by-step explanation:

5/24=0.2083333333

5 is 20.8% of 24

36*0.2083333333=7.4999999988

4 0

2 years ago

Read 2 more answers

Isabella's teacher said she must read more than 70 pages of her book by the end of the week. Isabella is able to read 12 pages o

VARVARA [1.3K]

Answer:

Step-by-step explanation:

3 0

2 years ago

#4. Find the value of x and use it to find the length of CE, BD, and BE Find BD.

almond37 [142]

Answer:

x = 8
12 = BD
23 = BE
13 = CE

Step-by-step explanation:

We know that:

BD = 2x - 4
DE = 2x - 3 - 2
BE = 3x - 1
CE = 2x - 3

Solution:

(2x - 4) + (2x - 3 - 2) = 3x - 1
=> 2x - 4 + 2x - 3 - 2 = 3x - 1
=> 4x - 9 = 3x - 1
=> 4x - 3x = 9 - 1
=> x = 8
=> 2x - 4 = BD
=> 2(8) - 4 = BD
=> 16 - 4 = BD
=> 12 = BD
=> 3x - 1 = BE
=> 3(8) - 1 = BE
=> 24 - 1 = BE
=> 23 = BE
=> 2x - 3 = CE
=> 2(8) - 3 = CE
=> 16 - 3 = CE
=> 13 = CE

Hence, the answers are:

x = 8
12 = BD
23 = BE
13 = CE

5 0

2 years ago

Sarah is a computer engineer and manager and works for a software company. She receives a

daser333 [38]

Answer:

a) Number of projects in the first year = 90

b) Earnings in the twelfth year = $116500

Total money earned in 12 years = $969000

Step-by-step explanation:

Given that:

Number of projects done in fourth year = 129

Number of projects done in tenth year = 207

There is a fixed increase every year.

a) To find:

Number of projects done in the first year.

This problem is nothing but a case of arithmetic progression.

Let the first term i.e. number of projects done in first year = $a$

Given that:

$a_4=129\\a_{10}=207$

Formula for $n^{th}$ term of an Arithmetic Progression is given as:

$a_n=a+(n-1)d$

Where $d$ will represent the number of projects increased every year.

and $n$ is the year number.

$a_4=129=a+(4-1)d \\\Rightarrow 129=a+3d .....(1)\\a_{10}=207=a+(10-1)d \\\Rightarrow 207=a+9d .....(2)$

Subtracting (2) from (1):

$78 = 6d\\\Rightarrow d =13$

By equation (1):

$129 =a+3\times 13\\\Rightarrow a =129-39\\\Rightarrow a =90$

Number of projects in the first year = 90

b)

Number of projects in the twelfth year =

$a_{12} = a+11d\\\Rightarrow a_{12} = 90+11\times 13 =233$

Each project pays $500

Earnings in the twelfth year = 233 $\times$ 500 = $116500

Sum of an AP is given as:

$S_n=\dfrac{n}{2}(2a+(n-1)d)\\\Rightarrow S_{12}=\dfrac{12}{2}(2\times 90+(12-1)\times 13)\\\Rightarrow S_{12}=6\times 323\\\Rightarrow S_{12}=1938$

It gives us the total number of projects done in 12 years = 1938

Total money earned in 12 years = 500 $\times$ 1938 = $969000

8 0

2 years ago