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Cerrena [4.2K]
3 years ago
14

Whats the error? I SOLVED AND CHECKED. Is it correct? Im confused… pls help il will give brainliest

Mathematics
1 answer:
Alchen [17]3 years ago
7 0

Answer:

32 in represents perimeter u added length times width once which would only give half of the rectangle

Step-by-step explanation:

2(3w+8+w) =32

6w+16+2w =32

8w+16 = 32

8w=16

w=2

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Which of the following is a solution to the inequality below?
kap26 [50]

Answer:

V>-8

Step-by-step explanation:

The given inequality is :

4-V>12

Subtracting 4 from both sides.

4-V-4 > 12-4

-V>8

or

V>-8

So, the value of V is more than -8.

7 0
3 years ago
Answer please...................
Debora [2.8K]
It means that all values of x would make it true. Also take a look at the equation when we simplify:

4x + 7 = 1 + 4x + 6
Which simplified turns into
4x + 7 = 4x + 7

So no matter what value you put for x, it will be the same on both sides, making all values true for x.
5 0
3 years ago
Answers for both boxes please ​
adelina 88 [10]

Answer:

3,0

Step-by-step explanation:

7 0
3 years ago
Lim x-1 x³-2x²+3x-2/(2x^4-3x+1)
UkoKoshka [18]

Since the limit becomes the undetermined form

\displaystyle \lim_{x\to 1} \dfrac{x^3-2x^2+3x-2}{2x^4-3x+1} \to \dfrac{0}{0}

it means that both polynomials have a root at x=1. So, we can fact both numerator and denominator:

x^3-2x^2+3x-2 = (x-1)(x^2-x+2)

2x^4-3x+1 = (x-1)(2x^3+2x^2+2x-1)

So, the fraction becomes

\dfrac{(x-1)(x^2-x+2)}{(x-1)(2x^3+2x^2+2x-1)} = \dfrac{x^2-x+2}{2x^3+2x^2+2x-1}

Now, as x approaches 1, you have no problems anymore:

\displaystyle \lim_{x\to 1} \dfrac{x^2-x+2}{2x^3+2x^2+2x-1} \to \dfrac{2}{5}

4 0
3 years ago
The mean and standard deviation of a normal distribution are 150 and 12 respectively. What percentage of values lie between:
Semenov [28]

Answer:

Step-by-step explanation:

Use a calculator with built-in statistical functions.  The function applying here is normcdf(, the "cumulative density function."  

(a) The percentage of values lying between 138 and 162 is

norm(138,162, 150, 12), which comes out to 0.683, or 68.3%.

(b)  Find norm(126, 174, 150,12):  0.945, or 94.5%

(c)  Find norm(126,162, 150,12);  0.819, or 81.9%

(d) Find norm(162, 174,150,12):  0.136, or 13.6%

8 0
4 years ago
Read 2 more answers
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