Answer:
he area that is un-shaded is (x-3)(x-6).
The entire area is (2x+2)(3x-4).
Area of the shaded region is:
(2x+2)(3x-4) - (x-3)(x-6) =
(6x2-2x-8) - (x2-9x+18) =
6x2-2x-8-x2+9x-18 =
5x2+7x-26 hopes this help btw (;
Answer:
![e(2x^{2} -12x)-4x^{2}+C](https://tex.z-dn.net/?f=e%282x%5E%7B2%7D%20-12x%29-4x%5E%7B2%7D%2BC)
Step-by-step explanation:
We have been given an indefinite integral as
. We are asked to find the given integral.
Let us solve our given problem.
![\int \left(4x-12\right)e\:dx-\int 8x\:dx](https://tex.z-dn.net/?f=%5Cint%20%5Cleft%284x-12%5Cright%29e%5C%3Adx-%5Cint%208x%5C%3Adx)
Take out constant:
![e\int \left(4x-12\right)\:dx-8\int x\:dx](https://tex.z-dn.net/?f=e%5Cint%20%5Cleft%284x-12%5Cright%29%5C%3Adx-8%5Cint%20x%5C%3Adx)
![e(\int 4x\:dx -\int 12\right\:dx)-8\int x\:dx](https://tex.z-dn.net/?f=e%28%5Cint%204x%5C%3Adx%20-%5Cint%2012%5Cright%5C%3Adx%29-8%5Cint%20x%5C%3Adx)
![e(\frac{4x^{1+1}}{2} -12x)-8*\frac{x^{1+1}}{1+1}+C](https://tex.z-dn.net/?f=e%28%5Cfrac%7B4x%5E%7B1%2B1%7D%7D%7B2%7D%20-12x%29-8%2A%5Cfrac%7Bx%5E%7B1%2B1%7D%7D%7B1%2B1%7D%2BC)
![e(\frac{4x^{2}}{2} -12x)-8*\frac{x^{2}}{2}+C](https://tex.z-dn.net/?f=e%28%5Cfrac%7B4x%5E%7B2%7D%7D%7B2%7D%20-12x%29-8%2A%5Cfrac%7Bx%5E%7B2%7D%7D%7B2%7D%2BC)
![e(2x^{2} -12x)-4x^{2}+C](https://tex.z-dn.net/?f=e%282x%5E%7B2%7D%20-12x%29-4x%5E%7B2%7D%2BC)
Therefore, our required integral would be
.
Answer: answer is 96
Step-by-step explanation: you have to multiply 8 6 and 2 together to get your answer
Answer:
5.3 to the 4th power :)
Step-by-step explanation:
Answer:
Step-by-step explanation:
Ellie:; 105/3 = 35 wpm
Vivian: 120/4 = 30 wpm