How do i do Pythagorean Theorem? (bc its sooooooo hard and confusing0

Mathematics

1 answer:

Lana71 [14]3 years ago

4 0

Answer:

a^2 + b^2= c^2

Step-by-step explanation:

C is the long part of the triangle and a and b are the legs

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Part A: Factor 3x2c2 + 5xc2 − 2c2. Show your work. (4 points) Part B: Factor x2 + 6x + 9. Show your work. (3 points) Part C: Fac

Margarita [4]

Answer:

$\boxed{\mathrm{view \: explanation}}$

Step-by-step explanation:

A) 3x²c² + 5xc² - 2c²

Factor c² from all terms in the expression.

c²(3x² + 5x - 2)

Factor 3x² + 5x - 2

c²(3x-1)(x+2)

B) x² + 6x + 9

x² + 3x + 3x + 9

Factor common terms.

x(x+3)+3(x+3)

Take x+3 common.

(x+3)(x+3)

C) x² - 9

x² -3²

Apply formula : a² - b² = (a+b)(a-b)

(x+3)(x-3)

6 0

3 years ago

Read 2 more answers

What is the sum or product of 93+ (68+7)

serg [7]

93 + (68+7)
93 + (75)
168

6 0

3 years ago

Read 2 more answers

*please help me out if you know how to solve, last person I asked just put a random awnser for point, the problem is bellow and

kicyunya [14]

For both of these, we will divide the wanted outcome by the number of possible outcomes. We will end up with a decimal. A decimal multiplied by 100 becomes a percent.

[a] 50%

$\displaystyle \frac{\text{wanted outcomes}}{\text{possible outcomes}} =\frac{\text{student failed}}{\text{Period 2's class}} =\frac{12}{24} =0.5,\:0.5*100=50\%$

[b] 52%

$\displaystyle \frac{\text{wanted outcomes}}{\text{possible outcomes}} =\frac{\text{student failed from Period 3}}{\text{fails from both classes}} =\frac{13}{25} =0.52,$