The correct answer is the marble would weather more rapidly.
The weathering of the rock can be defined as the procedure of the erosion of the rock by various agents. The marble is a metamorphic form of the limestone. The limestone is easily affected by the hot and the humid climates. The rain and the atmospheric carbon dioxide get mix together form mild acids, this acid react with the limestone and causes the chemical changes. As a result, the marble is subjected to erosion in hot and humid climate.
Answer:
The dead matter is the food for microbes which respires and forms carbon dioxide in to the atmosphere. The dead matter is the food for the organism such as saprophytes and decomposers. If the plant or the soil is burnt carbon dioxide is released into the air.As a result some of these particles become soil.
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Q1. <span>What is the mass of 1 cup of water and 2 teaspoons of salt?
The answer is 258 g.
Density (D) is mass (m) divided by volume (V): D = m/V
So, m = D * V
According to the US units, the volume of 1 cup is: V = 236.6 cm</span>³.
The density of the water is: D = 1 g/cm³.
So, the mass of 1 cup of water is: m = 1 g/cm³ * 236.6 cm³ = 236.6 g.
According to the US units, the volume of 1 teaspoon is: V = 4.93 cm³.
The density of salt is: D = 2.17 g/cm³.
So, the mass of 1 teaspoon of salt is: m = 2.17 g/cm³ * 4.93 cm³ = 10.7 g.
The mass of 1 cup of water and 2 teaspoons of salt is
236.6 g + 2 * 10.7 g = 236.6 g + 21.4 g = 258 g.
Q2. <span>What is the density of 1 cup of water and 2 teaspoons of salt?
</span>The answer is 3.17 g/cm³.
Density (D) is mass (m) divided by volume (V): D = m/V
According to the US units, the volume of 1 cup is: V = 236.6 cm³.
The mass of 1 cup of water from question 1 is: m = 236.6 g.
So, the density of 1 cup of water is: D = 236.6 g / 236.6 cm³ = 1 g/cm³
According to the US units, the volume of 1 teaspoon is 4.93 cm³. The volume of 2 teaspoons is: V = 2 * 4.93 cm³ = 9.86 cm³.
The mass of 1 teaspoon of salt from question 1 is: m = 10.7 g. The mass of 2 teaspoons of salt is: m = 2 * 10.7 g = 21.4 g.
So, the density of 2 teaspoons of salt is: D = 21.4 g / 9.86 cm³ = 2.17 g/cm³
The density of 1 cup of water and 2 teaspoons of salt is:
1 g/cm³ + 2.17 g/cm³ = 3.17 g/cm³
Q3. <span>What is the mass of 1 cup of water and 3 teaspoons of salt?
The answer is 268.7 g.
</span>Density (D) is mass (m) divided by volume (V): D = m/V
So, m = D * V
According to the US units, the volume of 1 cup is: V = 236.6 cm³.
The density of the water is: D = 1 g/cm³.
So, the mass of 1 cup of water is: m = 1 g/cm³ * 236.6 cm³ = 236.6 g.
According to the US units, the volume of 1 teaspoon is: V = 4.93 cm³.
The density of salt is: D = 2.17 g/cm³.
So, the mass of 1 teaspoon of salt is: m = 2.17 g/cm³ * 4.93 cm³ = 10.7 g.
The mass of 1 cup of water and 3 teaspoons of salt is
236.6 g + 3 * 10.7 g = 236.6 g + 32.1 g = 268.7 g.
Q4. <span>What is the density of 1 cup of water and 3 teaspoons of salt?
The answer is 3.17 g/cm</span>³<span>
</span>Density (D) is mass (m) divided by volume (V): D = m/V
According to the US units, the volume of 1 cup is: V = 236.6 cm³.
The mass of 1 cup of water from question 1 is: m = 236.6 g.
So, the density of 1 cup of water is: D = 236.6 g / 236.6 cm³ = 1 g/cm³
According to the US units, the volume of 1 teaspoon is 4.93 cm³. The volume of 3 teaspoons is: V = 3 * 4.93 cm³ = 14.79 cm³.
The mass of 1 teaspoon of salt from question 1 is: m = 10.7 g. The mass of 3 teaspoons of salt is: m = 3 * 10.7 g = 32.1 g.
So, the density of 3 teaspoons of salt is: D = 32.1 g / 14.79 cm³ = 2.17 g/cm³
The density of 1 cup of water and 3 teaspoons of salt is:
1 g/cm³ + 2.17 g/cm³ = 3.17 g/cm³
Q5. What is the mass of 1 cup of water and 4 teaspoons of salt?
The answer is 279.4 g.
Density (D) is mass (m) divided by volume (V): D = m/V
So, m = D * V
According to the US units, the volume of 1 cup is: V = 236.6 cm³.
The density of the water is: D = 1 g/cm³.
So, the mass of 1 cup of water is: m = 1 g/cm³ * 236.6 cm³ = 236.6 g.
According to the US units, the volume of 1 teaspoon is: V = 4.93 cm³.
The density of salt is: D = 2.17 g/cm³.
So, the mass of 1 teaspoon of salt is: m = 2.17 g/cm³ * 4.93 cm³ = 10.7 g.
The mass of 1 cup of water and 4 teaspoons of salt is
236.6 g + 4 * 10.7 g = 236.6 g + 42.8 g = 279.4 g.
Q6. What is the density of 1 cup of water and 4 teaspoons of salt?
The answer is 3.17 g/cm³
Density (D) is mass (m) divided by volume (V): D = m/V
According to the US units, the volume of 1 cup is: V = 236.6 cm³.
The mass of 1 cup of water from question 1 is: m = 236.6 g.
So, the density of 1 cup of water is: D = 236.6 g / 236.6 cm³ = 1 g/cm³
According to the US units, the volume of 1 teaspoon is 4.93 cm³. The volume of 4 teaspoons is: V = 4 * 4.93 cm³ = 19.72 cm³.
The mass of 1 teaspoon of salt from question 1 is: m = 10.7 g. The mass of 4 teaspoons of salt is: m = 4 * 10.7 g = 42.8 g.
So, the density of 3 teaspoons of salt is: D = 42.8 g / 19.72 cm³ = 2.17 g/cm³
The density of 1 cup of water and 4 teaspoons of salt is:
1 g/cm³ + 2.17 g/cm³ = 3.17 g/cm³