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3 years ago

Six added to the quotient of 84 and seven

Mathematics

2 answers:

Nonamiya [84]3 years ago

4 0

Answer:

Step-by-step explanation:

don't listen to me this just from what I know.

Tomtit [17]3 years ago

4 0

Answer:

84 divided by 7 is 12 + 6 = 18

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How do you do metric Measures ?

Marina86 [1]

What are u specifically asking

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3 years ago

Find the distance between the points (3, -1) and (4, 6).

andrezito [222]

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{3}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[4-3]^2+[6-(-1)]^2}\implies d=\sqrt{(4-3)^2+(6+1)^2} \\\\\\ d=\sqrt{50}\implies d\approx 7.07$

6 0

3 years ago

Read 2 more answers

A box is x to inches high,(2x+3)inches wide, and (2x+5) of inches long. In terms of x, what is the volume (v) of the box?

Advocard [28]

Answer:

The volume of the box is $V=(4x^3+16x^2+15x)\ in^3$

Step-by-step explanation:

we know that

The volume of the box is equal to

$V=LWH$

where

L is the length of the box in inches

W is the width of the box in inches

H is the height of the box in inches

we have

$L=(2x+5)\ in\\W=(2x+3)\ in\\H=x\ in$

substitute in the formula

$V=(2x+5)(2x+3)x$

$V=(4x^2+6x+10x+15)(x)$

$V=(4x^2+16x+15)(x)$

$V=(4x^3+16x^2+15x)\ in^3$

6 0

3 years ago

A cone with diameter 20 yd and a height of 20<br> yd.

stich3 [128]

What would you like to know? The total surface area? The lateral surface area? The volume, perhaps? The radius?

5 0

3 years ago

Mari has 3 friends who are available to go with her to the movies, but she only has 2 extra tickets. How many different choices

aliina [53]

Answer:

3 different choices

Step-by-step explanation:

This problem is a combination problem: She has 3 friends, and we want to know how many groups of 2 friends there are. We can solve this using the combination of 3 choose 2:

C(3,2) = 3!(1! * 2!) = 3*2/2 = 3 possibilities

If we call her three friends A, B and C, the groups that can be formed are:

A and B

A and C

B and C

6 0

3 years ago