What may happen if a large number of computer users are attempting to access a Web site at the same time that you are

frutty [35]

Given:
surveyed 3/4 of the population
2/3 of the surveyed students are into school clubs or sports team.

Multiply the fractions:
1) Multiply numerators
2) Multiply denominators
3) Simplify fraction

3/4 * 2/3 = 3*2 / 4*3 = 6/12
6/12 can be simplified into 1/2

4a) 3 rows and 4 columns
4b) 2 of the rows gray
4c) 4 of the gray squares black
4d) 1/2 of the students participate in school clubs or sports team

7 0

3 years ago

3⋅f(−4)−3⋅g(−2)= -27

Reil [10]

Answer:

3⋅f(−4)−3⋅g(−2)= -27 is g = -9/2 +2f

Graph the line using the slope and y-intercept, or two points.

Slope:

6 0

3 years ago

A manufacturer considers his production process to be out of control when defects exceed 3%. In a random sample of 100 items, th

pochemuha

Answer:

The p-value of the test is of 0.2776 > 0.01, which means that the we accept the null hypothesis, that is, the manager's claim that this is only a sample fluctuation and production is not really out of control.

Step-by-step explanation:

A manufacturer considers his production process to be out of control when defects exceed 3%.

At the null hypothesis, we test if the production process is in control, that is, the defective proportion is of 3% or less. So

$H_0: p \leq 0.03$

At the alternate hypothesis, we test if the production process is out of control, that is, the defective proportion exceeds 3%. So

$H_1: p > 0.03$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.03 is tested at the null hypothesis

This means that $\mu = 0.03, \sigma = \sqrt{0.03*0.97}$

In a random sample of 100 items, the defect rate is 4%.

This means that $n = 100, X = 0.04$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.04 - 0.03}{\frac{\sqrt{0.03*0.97}}{\sqrt{100}}}$

$z = 0.59$

P-value of the test

The p-value of the test is the probability of finding a sample proportion above 0.04, which is 1 subtracted by the p-value of z = 0.59.

Looking at the z-table, z = 0.59 has a p-value of 0.7224

1 - 0.7224 = 0.2776

The p-value of the test is of 0.2776 > 0.01, which means that the we accept the null hypothesis, that is, the manager's claim that this is only a sample fluctuation and production is not really out of control.

4 0

2 years ago

15/3 = 5 4_7 + 5 2_3<br> b=?

OLEGan [10]

Answer:

válla si son brutos está bien fácil esa pregunta lo que pasa es que estoy haciendo mi trabajo

5 0

2 years ago

Read 2 more answers

You are given the equation 27bx7•cx8•7xd=455x27. If b and c are both integers greater than 1 and b less than cb

jolli1 [7]

Answer:

The question is not so clear and complete

Step-by-step explanation:

But for questions like this, since the equation has been given, what is expected is for us to make comparison, compare the RHS with the LHS or by method of comparing coefficients.

We follow the stated conditions since we are told that b and c are both integers which are greater than 1 and b is less than the product of cb. from these conditions, we can compare and get the values of b , c and d.

Another approach is to assume values, make assumptions with the stated conditions, however, our assumptions must be valid and correct if we substitute the assumed values of b, c and d in the equation, it must arrive at the same answer for the RHS. i.e LHS = RHS

5 0

2 years ago