Answer:
see attached
Step-by-step explanation:
The x-coordinate of the vertex is given by ...
x = -b/(2a)
for f(x) = ax^2 +bx +c.
We see that the vertex is at x = 1, and we are given a = -16. Then we can find "b" from ...
1 = -b/(2(-16))
32 = b
We know the y-intercept of the equation is 5 (the starting height), so the equation must be ...
h(t) = -16t^2 +32t +5 . . . . . matches the last choice
2x2 + x −#6 _____________
x2 − 1
∙ x
__
2 + 2x + 1
x 2 − 4
Rewrite as multiplication.
(2x − 3)(x + 2) __
(x + 1)(x − 1) ∙ (x + 1)(x + 1) __ (x + 2)(x − 2) Factor the numerator and denominator.
(2x − 3)(x + 2)(x + 1)(x + 1) ___ (x + 1)(x − 1)(x + 2)(x − 2) Multiply numerators and denominators.
(2x − 3)(x + 2)(x + 1)(x + 1) ___ (x + 1)(x − 1)(x + 2)(x − 2) Cancel common factors to simplify.
(2x − 3)(x + 1) __ (x − 1)(x − 2)
Step-by-step explanation:
(n-m) out of n
not sure if this is correct or something....
Is there an image so I can see
