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kogti [31]
2 years ago
10

It takes 62 pounds of seed to completely plant an 8-acre field. How many pounds of seed are needed per acre

Mathematics
1 answer:
Mandarinka [93]2 years ago
4 0
7.75 pounds of seed are needed per acre
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Mohamed decided to track the number of leaves on the tree in his backyard each year The first year there were 500 leaves Each ye
svetlana [45]

Answer:

The required recursive formula is

f(n)= 500\times(1.4)^{n-1}\\

Step-by-step explanation:

Mohamed decided to track the number of leaves on the tree in his backyard each year.

The first year there were 500 leaves

Year \: 1 = 500

Each year thereafter the number of leaves was 40% more than the year before so that means

Year \: 2 = 500(1+0.40) = 500\times 1.4\\

For the third year the number of leaves increase 40% than the year before so that means

Year \: 3 = 500\times 1.4(1+0.40) = 500 \times 1.4^{2}\\

Similarly for fourth year,

Year \: 4 = 500\times 1.4^{2}(1+0.40) = 500\times 1.4^{3}\\

So we can clearly see the pattern here

Let f(n) be the number of leaves on the tree in Mohameds back yard in the nth year since he started tracking it then general recursive formula is

f(n)= 500\times(1.4)^{n-1}\\

This is the required recursive formula to find the number of leaves for the nth year.

Bonus:

Lets find out the number of leaves in the 10th year,

f(10)= 500\times(1.4)^{10-1}\\\\f(10)= 500\times(1.4)^{9}\\\\f(10)= 500\times20.66\\\\f(10)= 10330

So there will be 10330 leaves in the 10th year.

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3 years ago
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31.Helppoo with 31. Work and explanation of why
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The answer is C. $47.22
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3 years ago
One grain of this sand approximately weighs 6 x 10^-6g.
emmasim [6.3K]

Answer:

  • 1.2×10¹² grains

Step-by-step explanation:

1 grain = 6×10⁻⁶ g

  • 7200 kg =
  • 7200000 g =
  • 7.2×10⁶ g =
  • 7.2×10⁶ ÷ 6×10⁻⁶ =
  • (7.2÷6)×10⁶⁻ ⁽⁻⁶⁾ =
  • 1.2×10¹² grains
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2 years ago
Need help a s a p HURRYYYYY
Dimas [21]

Step-by-step explanation:

v= 4/3πr³

4/3×314/100×8×8×8

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= 2,143.573

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3 years ago
Write an equation perpendicular to x = 5 that passes through the point (-4,3)
Neporo4naja [7]

Answer:

y-y1=m(x-x1)

y-3=5(x+4)

y-3=5x+20

y-5x+3+20=0

y-5x+23=0

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