Answer:
5
Step-by-step explanation:
-2^2=-4
3^2=9
add
-4+9=5
Okay so for 2x-y > 3
Subtract -2 from each side
-y>-2x+3
Divide by -1
And when you divid you gotta switch signs
So it’s y<2x-3
3x-5y less than and equal to 25
Subtract 3
-5y is less than and equal to -3x+25
Then divide by -5
Flip since we divide
Y more than and equal to 3/5x-5
We always flip signs when we divid or multiple
I hope this help
Sorry if I’m wrong
A turning point occurs when the velocity is equal to zero, but the acceleration is not equal to zero.
t(x)=(x+5)^3+7
dt/dx=3(x+5)^2
d2t/dx2=6(x-5)
dt/dx=0 only when x=-5
However, since d2t/dx2(-5)=0, this point is an inflection point, not a turning point.
So there is no turning point for this function.
Now in this problem, it is even easier than the above to show that there is no turning point. A turning point by definition is when the derivative or velocity changes sign. Since in this case v=3(x+5)^2, for any value of x, v≥0, and thus never becomes negative, so it never changes from a positive to negative velocity because velocity in this instance is a squared function.
