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Ira Lisetskai [31]
3 years ago
9

Plss help i need help i beg you!!!!

Mathematics
1 answer:
Viktor [21]3 years ago
3 0

Answer:

Merry Berry

Why:

Put simply due to math you can see that the 6 cups is more than half of the water added so you have a fruitier drink in comparison to the other.

Hope this helped

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Find the sum of the first 6 terms in the sequence -5 -25 -125 -625
sashaice [31]
This is a geometric sequence, so use the formula for the sum of a geometric sequence:
Sum = (a(r^n - 1))/(r - 1)
where a is the first term, -5
r is the common ratio, 5
and n is the number of terms

Thus,
Sum = ((-5)(5^6 - 1))/(5-1) = -19530
5 0
3 years ago
One large bubble separates into four small bubbles so that the total area of the small bubbles is equal to the area of the large
anzhelika [568]

Answer:

10 cm.

Step-by-step explanation:

We'll begin by calculating the area of the small bubble. This can be obtained as follow:

Radius (r) = 5 cm

Area (A) =?

Since the bubble is circular in nature, we shall use the formula for area of circle to determine the area of the bubble. This is illustrated below:

A = πr²

A = π × 5²

A = 25π cm²

Next, we shall determine the total area of the small bubbles. This can be obtained as follow:

Area of 1 bubble = 25π cm²

Therefore,

Area of 4 bubbles = 4 × 25π cm²

Area of 4 bubbles = 100π cm²

Finally, we shall determine the radius of the large bubble. This can be obtained as follow:

Area of large bubble = total area of small bubbles = 100π cm²

Radius (r) =?

A = πr²

100π = πr²

100 = r²

Take the square root of both side

r = √100

r = 10 cm

Thus, the radius of the large bubble is 10 cm

5 0
2 years ago
3. The population P in thousands of a city can be modeled by the equation
madreJ [45]

Answer:

27 years

Step-by-step explanation:

P is measured in thosands therefore, P will have a value of 120

so it would be...

120=80e^0.015t

80e^0.015t=120

e^0.015t=120/80=3/2=1.5

e^0.015t=1.5

0.015t= In(1.5)

t=In(1.5)/0.015

∴ t≈27.03 round it to 27 years

It would be greatly appreciated if you gave me the brainlest

7 0
2 years ago
For what values of θ on the polar curve r=θ, with 0≤θ≤2π , are the tangent lines horizontal? Vertical?
Bond [772]
Given that r=\theta, then r'=1

The slope of a tangent line in the polar coordinate is given by:

m= \frac{r'\sin\theta+r\cos\theta}{r'\cos\theta-r\sin\theta}

Thus, we have:

m= \frac{\sin\theta+\theta\cos\theta}{\cos\theta-\theta\sin\theta}



Part A:

For horizontal tangent lines, m = 0.

Thus, we have:

\sin\theta+\theta\cos\theta=0 \\  \\ \theta\cos\theta=-\sin\theta \\  \\ \theta=- \frac{\sin\theta}{\cos\theta} =-\tan\theta

Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are horizontal are:

</span><span>θ = 0

</span>θ = <span>2.02875783811043
</span>
θ = <span>4.91318043943488



Part B:

For vertical tangent lines, \frac{1}{m} =0

Thus, we have:

\cos\theta-\theta\sin\theta=0 \\  \\ \Rightarrow\theta\sin\theta=\cos\theta \\  \\ \Rightarrow\theta= \frac{\cos\theta}{\sin\theta} =\sec\theta

</span>Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are vertical are:

</span>θ = <span>4.91718592528713</span>
3 0
3 years ago
When you went to sleep, the temperature was −2.8°C.
galben [10]

D

The larger the number the warmer it is

7 0
3 years ago
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