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svp [43]
3 years ago
6

If a semi-circle was rotated about the y-axis, like the one shown below, what would be the resulting three-dimensional shape?

Mathematics
2 answers:
nikdorinn [45]3 years ago
7 0

Answer:

Step-by-step explanation:

This rotation would create a sphere.

RoseWind [281]3 years ago
3 0

Answer:

sphere is correct

Step-by-step explanation:

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Mr mistry has 3 grandchildren. He gives Nimisha £m. He gives Sunhil £80 less than Nimisha. He gives Akshay twice as much as Sunh
slamgirl [31]
Here are the variables.

M= nimisha money

S= Sunhil money

A= Akshay money

The expression is S= M-80
A= S*2
M=S+80

Hope this helped

7 0
3 years ago
Read 2 more answers
let sin(θ) =3/5 and tan(y) =12/5 both angels comes from 2 different right trianglesa)find the third side of the two tringles b)
statuscvo [17]

In a right triangle, we haev some trigonometric relationships between the sides and angles. Given an angle, the ratio between the opposite side to the angle by the hypotenuse is the sine of this angle, therefore, the following statement

\sin (\theta)=\frac{3}{5}

Describes the following triangle

To find the missing length x, we could use the Pythagorean Theorem. The sum of the squares of the legs is equal to the square of the hypotenuse. From this, we have the following equation

x^2+3^2=5^2

Solving for x, we have

\begin{gathered} x^2+3^2=5^2 \\ x^2+9=25 \\ x^2=25-9 \\ x^2=16 \\ x=\sqrt[]{16} \\ x=4 \end{gathered}

The missing length of the first triangle is equal to 4.

For the other triangle, instead of a sine we have a tangent relation. Given an angle in a right triangle, its tanget is equal to the ratio between the opposite side and adjacent side.The following expression

\tan (y)=\frac{12}{5}

Describes the following triangle

Using the Pythagorean Theorem again, we have

5^2+12^2=h^2

Solving for h, we have

\begin{gathered} 5^2+12^2=h^2 \\ 25+144=h^2 \\ 169=h^2 \\ h=\sqrt[]{169} \\ h=13 \end{gathered}

The missing side measure is equal to 13.

Now that we have all sides of both triangles, we can construct any trigonometric relation for those angles.

The sine is the ratio between the opposite side and the hypotenuse, and the cosine is the ratio between the adjacent side and the hypotenuse, therefore, we have the following relations for our angles

\begin{gathered} \sin (\theta)=\frac{3}{5} \\ \cos (\theta)=\frac{4}{5} \\ \sin (y)=\frac{12}{13} \\ \cos (y)=\frac{5}{13} \end{gathered}

To calculate the sine and cosine of the sum

\begin{gathered} \sin (\theta+y) \\ \cos (\theta+y) \end{gathered}

We can use the following identities

\begin{gathered} \sin (A+B)=\sin A\cos B+\cos A\sin B \\ \cos (A+B)=\cos A\cos B-\sin A\sin B \end{gathered}

Using those identities in our problem, we're going to have

\begin{gathered} \sin (\theta+y)=\sin \theta\cos y+\cos \theta\sin y=\frac{3}{5}\cdot\frac{5}{13}+\frac{4}{5}\cdot\frac{12}{13}=\frac{63}{65} \\ \cos (\theta+y)=\cos \theta\cos y-\sin \theta\sin y=\frac{4}{5}\cdot\frac{5}{13}-\frac{3}{5}\cdot\frac{12}{13}=-\frac{16}{65} \end{gathered}

4 0
1 year ago
Pls show work <br> (-3*4) to the power of 3
Alex Ar [27]

Answer:

(-3*4)^3= -1728

Step-by-step explanation:

remember that

(-3*4)^3 is the same as (-3)^3 * (4)^3

Therefore,

-3^3 * 4^3

-27 * 64

= -1728

hope this helps :)

8 0
3 years ago
6x - (4x – 9) = 25 – 9<br> -True<br> -False
jolli1 [7]

Answer:

Step-by-step explanation:

6x-4x+9=25-9

2x=25-18

2x=7

x=3.5

8 0
3 years ago
Read 2 more answers
-1/5(x-4)=-2 how do you solve this equation
m_a_m_a [10]
Multiple both sides by 5/1 and get

-1/1 • (x-4) = -10/1

divide the numbers and get

-1 • (x-4) = -10

remove the parentheses

- x-4 = 10

move the constant to the right

-x = -10-4

calculate

-x = -14

change the signs

x= 14
8 0
3 years ago
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