You have to calculate how many combinations of 6 people can be chosen from 11. The formula for this is:
n! / [r! * (n-r)!]
combinations = 11! / [6! * 5!] =
11 * 10 * 9 * 8 * 7 / 5 * 4 * 3 * 2 *1 =
11 * 3 * 2 * 7 =
462 Combinations
Source:
http://www.1728.org/combinat.htm
First, isolate the variable, you can do this by adding 1.1. You're then left with z = 3.3, which is also the answer!
So looking at this from my bed, as a bored 11 year old, 2,910 is the rounded version of 2,912. Not to make you do work or anything but 2,910 divided by 95!
Answer:
1/9
Step-by-step explanation:
Answer:
a
Step-by-step explanation:
