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Ne4ueva [31]
3 years ago
10

2) The coordinates of the vertices of quadrilateral ABCD are A(-1,8),

Mathematics
1 answer:
Verizon [17]3 years ago
3 0

Answer:

The coordinates of vertices of A'B'C'D' are:

A'(1,-8), B'(0,-4), C'(2,-1) and D'(4,-3)

Step-by-step explanation:

When a point (h,k) is roated 180 degrees about the origin it becomes (-h,-k) which means that the new point after rotation is the negative of the previous.

Given vertices are:

A(-1,8),  B(0,4), C(-2,1), and D(-4,3)

The new vertices will be:

A(-1,8) => A'(1,-8)\\B(0,4)=> B'(0,-4)\\C(-2,1)=> C'(2,-1)\\D(-4,3)=> D'(4,-3)

The coordinates of vertices of A'B'C'D' are:

A'(1,-8), B'(0,-4), C'(2,-1) and D'(4,-3)

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Answer:

<h2>5, 7, 11</h2>

Step-by-step explanation:

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A prime number has only two divisors: 1 and itself.

Therefore, the prime numbers are:

5, 7 and 11.

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3 years ago
Step 1: Using one-step equations to solve problems.
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2 years ago
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3 years ago
4/3 b + 2 equals 4 - 1/3 be​
DIA [1.3K]

I do not understand what you are asking but I am going to assume that you are trying to simplify the equation.

First, write the equation.

(4/3)b + 2 = 4 - (1/3)b

Add (1/3)b to each side.

(5/3)b + 2 = 4

Subtract 2 on each side.

(5/3)b = 2

Divide by (5/3) on each side

b = 1.2

b = 1.2 is your final answer.

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