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iogann1982 [59]
3 years ago
13

Which one of the following foods is an example of a healthy dessert treat?

Mathematics
2 answers:
OLEGan [10]3 years ago
6 0

Answer:


The answer is A.

fruit is healthier than the other options. As fro D (which inclides fruit slices) icecream has more fat than sorbet.


s344n2d4d5 [400]3 years ago
3 0
Sorbet with fresh berries is an example of a healthy dessert treat. The correct option in regards to the question given is option "A". Fresh fruits are always considered healthy. In the first case, there are fresh berries included. In the case of option "A" the ingredients have less amount of fat and so should be considered healthy. In the case of the other dessert options given, there are ingredients that have good amount of fat. Although the last option contains sliced bananas, but it is combined with ice cream. Ice cream has huge amount of fat in it.
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C.126<br> D.115<br> Geometry math question no Guessing and Please show work
-BARSIC- [3]

The triangles are said to be similar, so the measures of sides in the larger triangle are proportional to the measures of sides in the smaller triangle. The measures of the two long sides have the ratio 182:65, so we expect the ratio of the shortest sides to be the same:

... ? : 45 = 182 : 65 . . . or . . . ?/45 = 182/65

Multiplying the equation by 45 gives us

... ? = 45·(182/65) = 126

The appropriate choice is ...

... C. 126


5 0
3 years ago
Vertex of y = x³ + x² - 4x - 4​
Firlakuza [10]

Answer:

(-2,0)

Step-by-step explanation:

5 0
3 years ago
A random sample of 121 students from the University of Oklahoma had a sample mean ACT score of 23.4 with a sample standard devia
Grace [21]

Answer:

(22.74,24.06) is the required 95% confidence interval for the population mean ACT score of University of Oklahoma students.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 121

Sample mean = 23.4

Sample standard deviation = 3.65

Level of significance = 0.05

Degree of freedom

= n - 1 = 120

95% Confidence interval:  

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Calculation of critical value:

t_{critical}\text{ at degree of freedom 120 and}~\alpha_{0.05} = \pm 1.9799  

Putting the values, we get,  

23.4\pm 1.9799(\dfrac{3.65}{\sqrt{121}} )\\\\ = 23.4 \pm 0.6569\\\\ = (22.7431 ,24.0569)\approx (22.74,24.06)  

(22.74,24.06) is the required 95% confidence interval for the population mean ACT score of University of Oklahoma students.

5 0
3 years ago
If the quotient of 18 3/5 is increased by 10 whats the solution?
andrew-mc [135]

40 i belive but im not sure

6 0
3 years ago
Please answer this question !! 20 points and brainliest !!
lawyer [7]

Answer: b.2x

Step-by-step explanation:

why? because 2 can be divided into all of the numbers evenly!

all the numbers have (x)

it wouldn't be (2x^2) ,because one of the numbers have x^3

5 0
3 years ago
Read 2 more answers
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