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kramer
3 years ago
5

HELP PLEASE!!!

Mathematics
1 answer:
mr Goodwill [35]3 years ago
3 0
The answer is a




Hahah
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Quick Computing Company produces
olganol [36]

Answer:

c(x) = 2x^2 + 6x + 25

Completed question;

Quick Computing Company produces calculators. They have found that the cost, c(x), of making x calculators is a quadratic function in terms of x. The company also discovered that it costs $45 to produce 2 calculators, $81 to produce 4 calculators, and $285 to produce 10 calculators. Derive the function c(x).

Step-by-step explanation:

Given that;

the cost, c(x), of making x calculators is a quadratic function in terms of x.

c(x) = ax^2 + bx + c

Substituting the 3 case scenarios given;

it costs $45 to produce 2 calculators,

45 = a(2^2) + b(2) + c

45 = 4a + 2b +c .......1

$81 to produce 4 calculators,

81 = a(4^2) + b(4) + c

81 = 16a + 4b + c .......2

and $285 to produce 10 calculators.

285 = a(10^2) + b(10) + c

285 = 100a + 10b + c .......3

Solving the simultaneous equation;

Subtracting equation 1 from 2, we have;

36 = 12a + 2b ......4

Subtracting equation 1 from 3

240 = 96a + 8b .......5

Multiply equation 4 by 4

144 = 48a + 8b ......6

Subtracting equation 6 from 5, we have;

96 = 48a

a = 96/48

a = 2

Substituting a = 2 into equation 4;

36 = 12(2) + 2b

36 = 24 + 2b

2b = 36-24 = 12

b = 12/2 = 6

b = 6

Substituting a and b into equation 1;

45 = 4(2) + 2(6) +c

45 = 8 + 12 + c

c = 45 - (8+12)

c = 25

Since a = 2 , b = 6 and c = 25, the quadratic equation for c(x) is ;

c(x) = ax^2 + bx + c

c(x) = 2x^2 + 6x + 25

5 0
2 years ago
In triangle ABC, the side lengths are AB = 13, AC = 21, and BC = x. Write a compound inequality that represents the range of pos
N76 [4]

There is only 1 solution for the length of BC.

We can calculate it using Pythagorean theorem.

We can conclude that triangle's hypotenuse is AC.

AC^2=AB^2+BC^2

If that is the case we are looking for a side BC.

BC=\sqrt{AC^2-AB^2}

Now put in the data.

BC=\sqrt{21^2-13^2}=\sqrt{272}=\sqrt{272}\approx\boxed{16.49}

Hope this helps.

r3t40

7 0
3 years ago
What is the area of the shaded region in the given circle in terms of pi and in simplest form?
BartSMP [9]

Answer:

Area of the shaded portion = (120π + 36√3)sq. m

Step-by-step explanation:

Area of the shaded region = Area of circle - Area of triangle

Given

radius of the circle = 12m

Area of the circle = πr²

Area of the circle  = π(12)²

Area of the circle  = 144π m²

Area of the sector = theta/360 * πr²

Area of the sector =  60/360 * 12²π

Area of the sector = 60/360 * 144π  = 24π

Area of the triangle = 1/2 bh

Area of the triangle = 1/2 (12cos30)(12)

Area of the triangle = 36√3

Area of the shaded portion = (144π - 24π + 36√3)sq. m

Area of the shaded portion = (120π + 36√3)sq. m

7 0
3 years ago
Help is it A or B? pls help
Damm [24]

Answer:

f(x)=-(x+8)(x-2)

Step-by-step explanation:

Start by factoring out a -1...

f(x)=-(x^2+6x-16)

Now, we have to find two integers that multiply to get -16 and have a sum of 6:

(-2)*8=-16

-2+8=8-2=6

Using this, we can split 6x into -2x and 8x...

f(x)=-(x^2-2x+8x+16)

Factor  the first and second half separately...

f(x)=-[(x^2-2x)+(8x-16)]\\f(x)=-[x(x-2)+8(x-2)]\\

Since both x and 8 are being multiplied by x-2, we can combine them to get...

f(x)=-(x+8)(x-2)

5 0
2 years ago
A construction company is building an above-ground parking garage. From one end of the entrance ramp to the other, the rise is 1
SVEN [57.7K]
The ramp is simply a right triangle when viewed from the side. The rise is the height of the triangle and the run is the length or base. The slope of the ramp is the angle that the ramp makes with the ground. Plug those values into the formula for tanФ = opposite/adjacent or rise/run and solve for Ф. You should end up with 0.23
6 0
2 years ago
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