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alexandr402 [8]
2 years ago
12

The length of a rectangle is 2 inches more than a number. The width is 1 inch less than twice the same number. If the area of th

e rectangle is 42 in2 find the dimensions of the rectangle
Mathematics
1 answer:
Tanya [424]2 years ago
6 0

Answer:

length: 6 inches

width: 7 inches

Step-by-step explanation:

Let n represent the number. Then the length is (n+2) and the width is (2n-1). The product of these dimensions is the area:

42 = (n+2)(2n -1) = 2n^2 +3n -2

2n^2 +3n -44 = 0 . . . . subtract 42

(n -4)(2n +11) = 0 . . . . . factor

n = 4 . . . . . . . . we aren't interested in the negative solution

Length = 4+2 = 6 . . . inches

Width = 2·4 -1 = 7 . . . inches

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What number is half way between 21 and 63?
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Factor.<br> x*2+11x+28<br> please give me the answer
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7 0
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Each bag of apples weighs 4 1/2 lb how much do 6 bags weigh?
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7 0
3 years ago
PLEASE HELP ME I WILL GIVE YOU POINTS
Brilliant_brown [7]

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Step-by-step explanation:

so for getting the perimeter, you only need the outer line, so you sum the measurements you have for the rectangle: 1+2+2+7= 12. After that you need the circumference of the circle, you can figure it out by using the formula C = 2pi(r) You can find the radius by substracting the known sides of the rectangle attached to the circle from the bottom base and then dividing it in 2, leaving us with a radius of 2. Then we input values; C=2pi(2) which equals 4pi, but we need to divide that in half since it’s only half a circle. That leaves us with 2pi, or 6.28. Then we add the perimeter of the square, which was 12, and 6.28+12= 18.28

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2 years ago
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