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3 years ago

Howto solve for x in X+10=30

Mathematics

2 answers:

Alla [95]3 years ago

3 0

Answer:

Step-by-step explanation:

x+10=30

x=30-10

x=20

<h2>HOPE IT HELPED </h2>

Len [333]3 years ago

3 0

Step-by-step explanation:

<h2>=>x+10=30</h2><h2>=>x+10-10=30-10 ten(+10) will be cancelled by negative ten(-10)</h2><h2>=>x=20</h2>

check

20+10=30

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Find the point at which the line joining the two points (-3,-5) and (7,5) cuts they y axis

8090 [49]

Answer:

(0,-2)

Step-by-step explanation:

First we find the equation of the line passes through $(-3,-5)$ and $(7,5)$ .

The slope of the line is

$m=\frac{5-(-5)}{7-(-3)}\\=\frac{10}{10}\\=1$

So by the point slope formula the equation of the line is

$y-5=1(x-7)\\y=x-7+5\\y=x-2$

When $x=0$ we have $y=0-2=-2$ .

Therefore the line joining the two points cuts the y-axis at (0,-2).

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2 years ago

I need help figuring this out asap please

Vera_Pavlovna [14]

Answer:

38.13 ft squared

Step-by-step explanation:

Since it is half of a circle we first find the area of a normal circle then divide by two.

So to find the area of a circle it is pi times radius squared which in this case it would be 3.14 times 9 = 28.26

Then since it is a half circle we divide by two so

28.26/2 = 14.13

Then to find the area of the triangle we do 4 times 6 which is 24.

now we add the two which is 14.13 + 24 which is

38.13

4 0

3 years ago

NO LINKS OR FILES!

Archy [21]

(a) If the particle's position (measured with some unit) at time t is given by s(t), where

$s(t) = \dfrac{5t}{t^2+11}\,\mathrm{units}$

then the velocity at time t, v(t), is given by the derivative of s(t),

$v(t) = \dfrac{\mathrm ds}{\mathrm dt} = \dfrac{5(t^2+11)-5t(2t)}{(t^2+11)^2} = \boxed{\dfrac{-5t^2+55}{(t^2+11)^2}\,\dfrac{\rm units}{\rm s}}$

(b) The velocity after 3 seconds is

$v(3) = \dfrac{-5\cdot3^2+55}{(3^2+11)^2} = \dfrac{1}{40}\dfrac{\rm units}{\rm s} = \boxed{0.025\dfrac{\rm units}{\rm s}}$

$\dfrac{-5t^2+55}{(t^2+11)^2} = 0 \implies -5t^2+55 = 0 \implies t^2 = 11 \implies t=\pm\sqrt{11}\,\mathrm s \imples t \approx \boxed{3.317\,\mathrm s}$

(d) The particle is moving in the positive direction when its position is increasing, or equivalently when its velocity is positive:

$\dfrac{-5t^2+55}{(t^2+11)^2} > 0 \implies -5t^2+55>0 \implies -5t^2>-55 \implies t^2 < 11 \implies |t|$

In interval notation, this happens for t in the interval (0, √11) or approximately (0, 3.317) s.

(e) The total distance traveled is given by the definite integral,

$\displaystyle \int_0^8 |v(t)|\,\mathrm dt$

By definition of absolute value, we have

$|v(t)| = \begin{cases}v(t) & \text{if }v(t)\ge0 \\ -v(t) & \text{if }v(t)$

In part (d), we've shown that v(t) > 0 when -√11 < t < √11, so we split up the integral at t = √11 as

$\displaystyle \int_0^8 |v(t)|\,\mathrm dt = \int_0^{\sqrt{11}}v(t)\,\mathrm dt - \int_{\sqrt{11}}^8 v(t)\,\mathrm dt$

and by the fundamental theorem of calculus, since we know v(t) is the derivative of s(t), this reduces to

$s(\sqrt{11})-s(0) - s(8) + s(\sqrt{11)) = 2s(\sqrt{11})-s(0)-s(8) = \dfrac5{\sqrt{11}}-0 - \dfrac8{15} \approx 0.974\,\mathrm{units}$

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2 years ago

Please help brainlist!

insens350 [35]

Answer:

4/8 - 2/8 = 2/8 = 1/4

Step-by-step explanation:

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3 years ago

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