Answer:
B
Step-by-step explanation:
Answer:
y = 3/2*x - 5
Step-by-step explanation:
Lets say that P1=(6,4) and P2=(4,1) and that the form of the equation must be y=m*x+b where m is the slope and b the independent variable. Then having two given points we can use the slope formula to find the slope value as:
P1=(x1,y1) and P2=(x2,y2)
slope formula ---> m=(y2-y1)/(x2-x1)
Replacing the given points ---> m=(1-4)/(4-6) = 3/2
then replacing the slope value obtained:
y = 3/2*x + b
Now lets find the value of b. For this we have to replace in the equation a point it can be P1 or P2, i will replace P2:
1 = 3/2*4 + b
1 = 6 + b
1 - 6 = b
-5 = b
therefore the line equation is:
y = 3/2*x - 5
A: 3.2/294=12/T
<span>T=1102.5 K </span>
<span>*** </span>
<span>*** </span>
<span>b: V/T => V/1088 = 4000/294 </span>
<span>V = 14802.7 L = 14.8 m^3 </span>
<span>*** </span>
<span>*** </span>
<span>c. </span>
<span>pV/T </span>
<span>1.1*V/294 = 12*15000/1088 </span>
<span>V= 48.64 m^3</span>
Begin by finding the lowest point the quadratic equation can be, the vertex;
x²-1= is just a translation down of the graph x²
vertex; (0, -1) and since the graph of x² would extend to infinity beyond that point, we can say {x| x≥0} for domain and {y| y≥-1}.
For the linear equation, it is possible to have all x and y values, therefore range and domain belong to all real numbers.
Hope I helped :)
Answer:
The answer is c.
Step-by-step explanation:
