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seropon [69]
3 years ago
7

(8.4x10^3)-(6.4x10^2) Write anserr in scientific notation

Mathematics
2 answers:
Nikolay [14]3 years ago
8 0
2x10^1 hope it helps!!
Alex_Xolod [135]3 years ago
7 0
I think the answer is 2x10^1
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FIND THE SLOPE OF THE LINE
schepotkina [342]

Answer:

4/1

Step-by-step explanation:

To get from one dot to the next, you go up by four and to the right by one, making the slope 4/1

3 0
2 years ago
Identify the vertex of the graph tell weather it is minimum or maximum
Contact [7]

Vertex is (-2,-3) and it's a minimum.

4 0
3 years ago
The admission fee at amusement park is $1.50 for children and $4 for adults on a certain day 355 ppl entered the park and the ad
antoniya [11.8K]

Answer:

180 children and 175 adults

Step-by-step explanation:

Let it be that the amount of children who visited the park that day was x, the rest was adults. It means the quantity of adults equals 355-x.

The payment from the children is 1.5*x (because each children payed 1.5 dollars, the amount of money from children is the fee from one child multiplied by the quantity of children). The money earned by the park's owners from adults are equal to the fee from one adult multiplied by the quantity  4* (355-x)= 1420 -4x

If we add the money from chilren and adults we get the summary profit of park (it is equal to 970 dollars)

1.5x+ 1420-4x= 970

1420-2.5x= 970

x=180- children

355-180=175adults

5 0
3 years ago
Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.
suter [353]

Answer:

\theta = 30^\circ, 330^\circ

\theta = \frac{\pi}{6}, \frac{11\pi}{6}

Step-by-step explanation:

Given [Missing from the question]

Equation:

cos\theta = \frac{\sqrt 3}{2}

Interval:

0 \le \theta \le 360

0 \le \theta \le 2\pi

Required

Determine the values of \theta

The given expression:

cos\theta = \frac{\sqrt 3}{2}

... shows that the value of \theta is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

cos\theta = \frac{\sqrt 3}{2}

Take arccos of both sides

\theta = cos^{-1}(\frac{\sqrt 3}{2})

\theta = 30 --- In the first quadrant

In the fourth quadrant, the value is:

\theta = 360 -30

\theta = 330

So, the values of \theta in degrees are:

\theta = 30^\circ, 330^\circ

Convert to radians (Multiply both angles by \pi/180)

So, we have:

\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}

\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}

\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}

\theta = \frac{\pi}{6}, \frac{11\pi}{6}

8 0
2 years ago
PLEASE HELP I WILL GIVE 100 POINTS!!!!!!!!Given rectangle ABCD ~ HGFE , what is the length of HG ?
never [62]
Since rectangle ABCD is similar to  HGFE, the ratios of the lengths of their corresponding sides are equal. We can infer form our picture that AD is corresponding to EH and DC is corresponding to HG, so lets find the ratios of those corresponding sides and establish a proportion to find the length of HG:
\frac{AD}{EH} = \frac{DC}{HG}
We know that AD=45, EH=27, and DC=15, so lets replace those values in our proportion:
\frac{45}{27} = \frac{15}{HG}
HG= \frac{27*15}{45}
HG= \frac{405}{45}
HG=9

We can conclude that the length of the segment HG is 9.

8 0
3 years ago
Read 2 more answers
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