Question

What is an equation of the line that passes through the point (-2,-6) and is parallel to the line x+2y=8x+2y=8?

Answer 1

Answer:

y= -x/2-7

Step-by-step explanation:

We need to write an equation of the line that passes through the point (-2, -6) and is  parallel to the line x + 2y = 8

We need to find slope m and y-intercept b for the new line.

First we need to find slope m of the new line.

The given line x+2y=8 is parallel to new line.

When lines are parallel, there slope is same.

First writing equation in slope-intercept form:  where m is slope and b is y-intercept

Now comparing with  the slope is :

Now finding y-intercept b

Using point (-2,-6) and slope  we can find y-intercept

So, we get y-intercept b = -7

Now the equation of required line having slope  and y-intercept b = -7 is:

So, the equation of new line is: