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Temka [501]
4 years ago
13

Mr. Kohl has a beaker containing n milliliters of solution to distribute to the students in his chemistry class. If he gives eac

h student 3 milliliters of solution, he will have 5 milliliters left over. In order to give each student 4 milliliters of solution, he will need an additional 21 milliliters. How many students are in the class?
Mathematics
1 answer:
elixir [45]4 years ago
6 0

Answer:

There are 26 students in the class

Step-by-step explanation:

Let n millilitres be the solution in the beaker

Let x be the number of students in a class

He gives 3 millilitres of solution to each student . He will have 5 millilitres left over.

So, Solution distributed = 3x

Remaining solution = n-3x

So, n-3x = 5 ----1

In order to give each student 4 millilitres of solution, he will need an additional 21 millilitres.

So, n-4x=-21 -----2

Substitute the value of n from 1 in 2

So, 5+3x-4x=-21

5-x=-21

26=x

Hence There are 26 students in the class

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Answer:

8%3-29xy

Step-by-step explanation:

thats the answer

4 0
1 year ago
Dante plans to put 80% of his paycheck into a savings account and spend the other 20%. His paycheck this week was 295$. About ho
IgorLugansk [536]

80% × $295 = 80/100 × $295 = $236

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6 0
3 years ago
Two quadratic functions are represented below.
Tpy6a [65]
To determine the maximum value of a quadratic function opening downwards, we are going to find the vertex; then the y-value of the vertex will be our maximum.
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So, in our function f(x)=- x^{2} +4x-3, a=-1 and b=4. 
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Now that we know the x-coordinate of our vertex, lets replace it in the original function, to get the y-coordinate:
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7 0
3 years ago
Read 2 more answers
Help me anyone that great in math
pochemuha

Answer:

B) 24/35

Step-by-step explanation:

Cos(X)= Adjacent/Hypotenuse

Cos(X) = 24/25

Therefore, option B is your answer.

Hope this answers your question!!

6 0
3 years ago
Solve the rational equation: 2x/x-4-2x-5/x^2-10x+24=-3/x-6
jek_recluse [69]

Answer:

D. X=6.08, x=-0.58

Step-by-step explanation:

Given the rational expression

\frac{2x}{x-4}-\frac{2x-5}{x^2-10x+24} = \frac{-3}{x-6}\\\frac{2x}{x-4}-\frac{2x-5}{x^2-4x-6x+24} = \frac{-3}{x-6}\\\frac{2x}{x-4}-\frac{2x-5}{x(x-4)-6(x-4)} = \frac{-3}{x-6}\\ \\\frac{2x}{x-4}-\frac{2x-5}{(x-4)(x-6)} = \frac{-3}{x-6}\\Rerrange;\\\frac{2x-5}{(x-4)(x-6)}  =  \frac{2x}{x-4}+ \frac{3}{x-6}\\\frac{2x-5}{(x-4)(x-6)}  =  \frac{2x(x-6)+3(x-4))}{(x-4)(x-6)}\\

Cancel out the denominator on both sides

2x-5 = 2x(x-6)+3(x-4)\\Expand\\2x-5 =2x^2-12x+3x-12\\2x-5 = 2x^2-9x-12\\Equate \ to \ zero\\2x^2-9x-12-2x+5 = 0\\2x^2-11x - 7 = 0\\

Factorize

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Hence the required solution is X=6.08 and -0.58

7 0
3 years ago
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