All categories

3 years ago

What is a integers?

Mathematics

2 answers:

Irina-Kira [14]3 years ago

6 0

<span>a whole number; a number that is not a fraction.</span>

Makovka662 [10]3 years ago

6 0

Integers are numbers. positive and negatives.

You might be interested in

Make d the subject of the formula h=d/3+2

Pani-rosa [81]

Answer: D=3(h-2)

Explanation —>

8 0

2 years ago

Which recursive formula can be used to generate the sequence shown, where f(1) = 5 and n > 1?

Degger [83]

The recursive formula $a_n = a_{n-1}-6$ can be used to generate the shown sequence

Step-by-step explanation:

Recursive formula is the formula that is used to generate the next term of a sequence using previous term.

The general form of arithmetic sequence's recursive formula is:

$a_n = a_{n-1}+d$

Given

5,-1,-7,-13,-19

Here

$a_1 = 5\\a_2 = -1\\a_3 = -7$

First of all we have to find the common difference of the sequence.

So,

$d = a_2 -a_1 = -1-5 = -6\\d = a_3-a_2 = -7+1 = -6$

Putting the value of d in the general recursive formula

$a_n = a_{n-1}-6$

Hence,

The recursive formula $a_n = a_{n-1}-6$ can be used to generate the shown sequence

Keywords: Sequence, arithmetic sequence

Learn more about arithmetic sequence at:

#LearnwithBrainly

8 0

3 years ago

Read 2 more answers

Write Three and eight thousandths in standard form? What is it

Lapatulllka [165]

Thousandths is the 3rd decimal place

The answer is 3.008

6 0

3 years ago

X + 3 < 15<br> what is 4

professor190 [17]

Answer:

X = > 12 because 15 - 3 = 12 and if X was more than 12 it would be wrong.

Step-by-step explanation:

6 0

2 years ago

How do I find roots from a quadratic equation

Trava [24]

Answer:The roots of any quadratic equation is given by: x = [-b +/- sqrt(-b^2 - 4ac)]/2a. Write down the quadratic in the form of ax^2 + bx + c = 0. If the equation is in the form y = ax^2 + bx +c, simply replace the y with 0. This is done because the roots of the equation are the values where the y axis is equal to 0.

Step-by-step explanation:

6 0

3 years ago