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3 years ago

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Dave sells popcorn at the ballpark. He is paid a flat rate of $40 each .day, but also earns $0.45 for each box of popcorn he sel

ls. Dave earns a total of $112 at Wednesday night’s game. How many boxes of popcorn does he sell?

2 answers:

kari74 [83]3 years ago

5 0

Answer:UMM SORRY I GTG IM GETTING TACO BELL WISH I COULD HELP SORRY I HOPE YOU GET IT IM CHEERING YOU ON WHOO HOO

HOORAYYYYYY!!!!!!!!!!!!!!!!!!!!!!!!!

Step-by-step explanation:

taurus [48]3 years ago

4 0

you have to count until 112

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Maria scored 72, 97, and 82 on her first three math tests. She wants to have a mean score of 82 for the quarter. How many points

Rom4ik [11]

Answer:

<em>She needs </em><em>77 </em><em>on her last test to earn an 82 for the quarter.</em>

Step-by-step explanation:

Maria scored 72, 97, and 82 on her first three math tests.

She wants to have a mean score of 82 for the quarter.

Let us assume that she must score x on her last test to earn an 82 for the quarter.

So the average score will be,

$=\dfrac{72+97+82+x}{4}$

But the average score is given as 82, so

$\Rightarrow \dfrac{72+97+82+x}{4}=82$

$\Rightarrow 72+97+82+x=82\times 4$

$\Rightarrow 72+97+82+x=328$

$\Rightarrow x=328-72-97-82$

$\Rightarrow x=77$

3 0

3 years ago

Read 2 more answers

Find constants a and b such that the function y = a sin(x) + b cos(x) satisfies the differential equation y'' + y' − 5y = sin(x)

vichka [17]

Answers:

a = -6/37

b = -1/37

============================================================

Explanation:

Let's start things off by computing the derivatives we'll need

$y = a\sin(x) + b\cos(x)\\\\y' = a\cos(x) - b\sin(x)\\\\y'' = -a\sin(x) - b\cos(x)\\\\$

Apply substitution to get

$y'' + y' - 5y = \sin(x)\\\\\left(-a\sin(x) - b\cos(x)\right) + \left(a\cos(x) - b\sin(x)\right) - 5\left(a\sin(x) + b\cos(x)\right) = \sin(x)\\\\-a\sin(x) - b\cos(x) + a\cos(x) - b\sin(x) - 5a\sin(x) - 5b\cos(x) = \sin(x)\\\\\left(-a\sin(x) - b\sin(x) - 5a\sin(x)\right) + \left(- b\cos(x) + a\cos(x) - 5b\cos(x)\right) = \sin(x)\\\\\left(-a - b - 5a\right)\sin(x) + \left(- b + a - 5b\right)\cos(x) = \sin(x)\\\\\left(-6a - b\right)\sin(x) + \left(a - 6b\right)\cos(x) = \sin(x)\\\\$

I've factored things in such a way that we have something in the form Msin(x) + Ncos(x), where M and N are coefficients based on the constants a,b.

The right hand side is simply sin(x). So we want that cos(x) term to go away. To do so, we need the coefficient (a-6b) in front of that cosine to be zero

a-6b = 0

a = 6b

At the same time, we want the (-6a-b)sin(x) term to have its coefficient be 1. That way we simplify the left hand side to sin(x)

-6a -b = 1

-6(6b) - b = 1 .... plug in a = 6b

-36b - b = 1

-37b = 1

b = -1/37

Use this to find 'a'

a = 6b

a = 6(-1/37)

a = -6/37

8 0

2 years ago

I need help pls someone:(

Svetlanka [38]

Answer:

7/30

Step-by-step explanation:

3 0

3 years ago

Which is bigger 5 and 3/8 in or 5 and 4/10 in

julsineya [31]

5 and 4/10 is bigger

6 0

3 years ago

Find an equation of the tangent to the curve at the given point by both eliminating the parameter and without eliminating the pa

jek_recluse [69]

Answer:2x-y=5

Step-by-step explanation:

Given

$x=6+\ln t$

$y=t^{2}+6$

$\left ( a\right )$ without eliminating parameter

$\frac{\mathrm{d} x}{\mathrm{d} t}$ = $\frac{1}{t}$

$\frac{\mathrm{d} y}{\mathrm{d} t}$ =2t

$\frac{\mathrm{d} y}{\mathrm{d} x}=2t^2$

at $\left ( 6,7\right )$

6=6+ $\ln\left ( t\right )$

t=1

Equation of line is given by

2= $\frac{y-7}{x-6}$

2x-12=y-7

2x-y=5

$\left ( b\right )$ by eliminating parameter

$x-6=\ln \left ( t\right )$

$t=e^{x-6}$

$y=t^2 +6$

$y=e^{\left ( 2x-12\right )}+6$

differentiating we get

$\frac{\mathrm{d}y}{\mathrm{d} x}=2e^\left ( 2x-12\right )$

$at \left ( 6,7\right )$

$\frac{\mathrm{d}y}{\mathrm{d} x}=2$

$2\left ( x-6\right )=\left ( y-7\right )$

2x-y=5

4 0

3 years ago