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iogann1982 [59]
3 years ago
15

Two puppies eat 2 cans of dog food in 2 days. How many cans of dog food can 8 puppies eat in 8 days? Note: All puppies eat at th

e same constant rate.
Mathematics
1 answer:
Dmitry [639]3 years ago
6 0

Answer:

64 cans

Step-by-step explanation:

If two puppies eat 2 cans in two days then you can imagine one puppy eats one and the other puppy eats the other. so if 8 puppies eat in 8 days you would want to do 8 * 8 = 64 cans

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A salesperson earns a salary of $700 per month plus 2% of the sales. Which inequality correctly represents the term total sales
gulaghasi [49]
Answer = B, because 2% of 55,000 equals $1,100 then you add the $700 salary bringing you to the minimum $1,800
5 0
3 years ago
Read 2 more answers
I need help with this assignment help
saw5 [17]

Table:

4 cups of water, 5 cups of flour.

9 cups of water, 10 cups of flour.

16 cups of water, 17 cups of flour.

29 cups of water, 30 cups of flour.

Equation:

f-1=w

Independent variable:

F

Dependent variable:

W

4 0
3 years ago
A survey of 100 people asked if they have a dog or a cat. The answers were: 56 people answered yes for dog and 51 people answere
den301095 [7]

Answer:  The maximum number of people who could answer yes for both cat and dog is 7.

Step-by-step explanation:  Given that a survey of 100 people asked if they have a dog or a cat.

Out of those 100 people, 56 people answered yes for dog and 51 people answered yes for cat. Some people may own neither and some people may own both animals.

We are to find the maximum number of people that could answer yes for both cat and dog.

Let A and B represents the set of people that answered Yes for dog and Yes for cat respectively.

Then, according to the given information, we have

n(A)=56,~~n(B)=51.

From Set Theory, we have

n(A\cup B)=n(A)+n(B)-n(A\cap B)\\\\\Rightarrow n(A\cup B)=56+51-n(A\cap B)\\\\\Rightarrow n(A\cup B)=107-n(A\cap B)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

Since the total number of people is 100, so we get

n(A\cup B)\geq 100.

Therefore, from equation (i), we get

107-n(A\cap B)\geq 100\\\\\Rightarrow n(A\cap B)\leq 107-100\\\\\Rightarrow n(A\cap B)\leq 7.

Thus, the maximum number of people who could answer yes for both cat and dog is 7.

4 0
3 years ago
Read 2 more answers
The 11th term of an progression is 25 and the sum of the first 4 terms is 49. The nth term of the progression is 49
KIM [24]

<u>Answer:</u>

<u>For 1:</u> The first term is 10 and the common difference is \frac{3}{2}

<u>For 2:</u> The value of n is 27

<u>Step-by-step explanation:</u>

The n-th term of the progression is given as:

a_n=a_1+(n-1)d

where,

a_1 is the first term, n is the number of terms and d is the common difference

The sum of n-th terms of the progression is given as:

S_n=\frac{n}{2}[2a_1+(n-1)d]

where,

S_n is the sum of nth terms

  • <u>For (1):</u>

The 11th term of the progression:

25=a_1+10d               .......(1)

Sum of first 4 numbers:

49=\frac{4}{2}[2a_1+3d              ......(2)

Forming equations:

98=8a_1+12d

25=a_1+10d                  ( × 8)

The equations become:

98=8a_1+12d

200=8a_1+80d

Solving above equations, we get:

102=68d\\\\d=\frac{102}{68}=\frac{3}{2}

Putting value in equation (1):

25=a_1+10\frac{3}{2}\\\\a_1=[25-15]=10

Hence, the first term is 10 and the common difference is \frac{3}{2}

  • <u>For 2:</u>

The nth term is given as:

49=10+(n-1)\frac{3}{2}

Solving the above equation:

39=(n-1)\frac{3}{2}\\\\n-1=26\\\\n=27

Hence, the value of n is 27

3 0
3 years ago
What is the area of the shaded region ??
alina1380 [7]

Answer:

B  0.6825

Step-by-step explanation:

From the tables

0.80 = 02881 of the area

1.25 = 0.3944 of the area

Sum of these 2 = 0.6825


3 0
3 years ago
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