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goblinko [34]
3 years ago
14

Is the problem 3 games played in 2.5 hours and 9 games played in 7.5 hours.

Mathematics
1 answer:
Flura [38]3 years ago
8 0
I think it’s proportional!
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What is the slope of the graph?
Ivahew [28]
The slope is 5/1 because b =5
6 0
3 years ago
Given: Tangents LA and LB, m∠AOB=110°. Find: m∠ALO.
Yuri [45]

Answer:

The measure of angle ALO = 35°

Step-by-step explanation:

* Lets talk about the tangents to a circle drawn from a point

 outside the circle:

- They are equal in length

- They are perpendicular to the radii at the point of tang-ency

- If we join the points of tang-ency withe the center of the circle

 and join the outside point with center of the circle, we

 formed two congruent triangles

* Now lets check our problem

- AL and LB are two tangents to the circle O ant points A and B

∴ LA = LB ⇒ (1)

- OA and OB are radii in circle O

∴ OA = OB ⇒ (2)

∴ OA ⊥ AL and OB ⊥ BL ⇒ radius and tangent

∴ m∠OAL = 90° , m∠OBL = 90

∴ m∠OAL = m∠OBL ⇒ (3)

* From (1) , (2) , (3)

- The two triangles LAO and LBO are congruent ⇒ SAS

- SAS is one case of congruence

∵ The lengths of two sides and the measure of the including

  angle between them in one triangle equal to the

  corresponding sides and angles in the second triangle,

  then the two triangles are congruent

∴ m∠LOA = m∠LOB

∵ m∠AOB = 110°

∴ m∠LOA = m∠LOB = 110/2 = 55°

* In ΔLAO

∵ m∠ LAO = 90° , m∠LOA = 55°

∴ m∠ALO = 180 - (90 + 55) = 180 - 145 = 35°

* The measure of angle ALO = 35°

8 0
4 years ago
Distance between (-4, -3) (2, 1)
VikaD [51]

Answer:

\Longrightarrow: \boxed{\sf{2\sqrt{13}}}

Step-by-step explanation:

<u>Question</u>:

  • Find the distance between (-4,-3) (2,1)

<u>To find:</u>

  • The distance between (-4,-3) (2,1).

Use the distance formula.

<u>Distance formula:</u>

\Longrightarrow: \sf{\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}}

\sf{y_2=1}\\\\\sf{y_1=(-3)}\\\\\sf{x_2=2}\\\\\sf{x_1=(-4)}

\Longrightarrow: \sf{\sqrt{\left(2-\left(-4\right)\right)^2+\left(1-\left(-3\right)\right)^2}

Solve.

\Longrightarrow: \boxed{\sf{2\sqrt{13}}}

  • <u>Therefore, the final answer is 2√13.</u>

I hope this helps, let me know if you have any questions.

8 0
2 years ago
Read 2 more answers
"Find an integer, x, such that 5, 10, and x represent the lengths of the sides of an acute triangle.
Contact [7]
A, b, c - the lengths of the sides of the triangle
and a ≤ b ≤ c
then:
a + b > c and if the triangle is an acute triangle then a² + b² > c².

1^o\\5\leq10\leq x\\\\\left\{\begin{array}{ccc}5+10 \ \textgreater \  x\\5^2+10^2 \ \textgreater \  x^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textless \  15\\ x^2 \ \textless \  125\end{array}\right\to\left\{\begin{array}{ccc}x \ \textless \  15\\ x \ \textless \  \sqrt{125}\approx11.1\end{array}\right\\\\\boxed{x=11}\\\\2^o\\5\leq x\leq10\\\\\left\{\begin{array}{ccc}5+x \ \textgreater \  10\\ 5^2+x^2 \ \textgreater \  10^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \  5\\ x^2 \ \textgreater \  75\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \  5\\ x \ \textgreater \  \sqrt{75}\approx8.7\end{array}\right\\\boxed{x=9}

3^o\\x\leq5\leq10\\\\\left\{\begin{array}{ccc}x +5 \ \textgreater \  10\\ x^2+5^2 \ \textgreater \  10^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x^2 \ \textgreater \ 75\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x \ \textgreater \ \sqrt{75}\approx8.7\end{array}\right\\\boxed{x\in\O}\\\\Answer:\boxed{x=9\ or\ x=11}\to your\ answer:\boxed{\boxed{x=11}}
8 0
4 years ago
Read 2 more answers
The value of the surface area of the cylinder is equal to the value of the volume of the cylinder. Find the value of x.
torisob [31]

Answer:

4gfuoe3

Step-by-step explanation:

6 0
3 years ago
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