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dezoksy [38]
3 years ago
8

Find the total surface area of this cylinder.

Mathematics
1 answer:
Natali5045456 [20]3 years ago
7 0

Answer

967.1  squared cm, multiply area of base by two, and perimeter by 15.

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27.38 + 384 -<br> I don’t know the answer can I please have some help
Katen [24]

Answer:

411.38

Step-by-step explanation:

When you add 27.38 and 384 together, you get 411.38.

3 0
3 years ago
12+3y+y=?<br> What is the answer?
puteri [66]

Answer:

12+4y

Step-by-step explanation:

12+3y+y=12+4y

3 0
3 years ago
Read 2 more answers
1. cot x sec4x = cot x + 2 tan x + tan3x
Mars2501 [29]
1. cot(x)sec⁴(x) = cot(x) + 2tan(x) + tan(3x)
    cot(x)sec⁴(x)            cot(x)sec⁴(x)
                   0 = cos⁴(x) + 2cos⁴(x)tan²(x) - cos⁴(x)tan⁴(x)
                   0 = cos⁴(x)[1] + cos⁴(x)[2tan²(x)] + cos⁴(x)[tan⁴(x)]
                   0 = cos⁴(x)[1 + 2tan²(x) + tan⁴(x)]
                   0 = cos⁴(x)[1 + tan²(x) + tan²(x) + tan⁴(4)]
                   0 = cos⁴(x)[1(1) + 1(tan²(x)) + tan²(x)(1) + tan²(x)(tan²(x)]
                   0 = cos⁴(x)[1(1 + tan²(x)) + tan²(x)(1 + tan²(x))]
                   0 = cos⁴(x)(1 + tan²(x))(1 + tan²(x))
                   0 = cos⁴(x)(1 + tan²(x))²
                   0 = cos⁴(x)        or         0 = (1 + tan²(x))²
                ⁴√0 = ⁴√cos⁴(x)      or      √0 = (√1 + tan²(x))²
                   0 = cos(x)         or         0 = 1 + tan²(x)
         cos⁻¹(0) = cos⁻¹(cos(x))    or   -1 = tan²(x)
                 90 = x           or            √-1 = √tan²(x)
                                                         i = tan(x)
                                                      (No Solution)

2. sin(x)[tan(x)cos(x) - cot(x)cos(x)] = 1 - 2cos²(x)
              sin(x)[sin(x) - cos(x)cot(x)] = 1 - cos²(x) - cos²(x)
   sin(x)[sin(x)] - sin(x)[cos(x)cot(x)] = sin²(x) - cos²(x)
                               sin²(x) - cos²(x) = sin²(x) - cos²(x)
                                         + cos²(x)              + cos²(x)
                                             sin²(x) = sin²(x)
                                           - sin²(x)  - sin²(x)
                                                     0 = 0

3. 1 + sec²(x)sin²(x) = sec²(x)
           sec²(x)             sec²(x)
      cos²(x) + sin²(x) = 1
                    cos²(x) = 1 - sin²(x)
                  √cos²(x) = √(1 - sin²(x))
                     cos(x) = √(1 - sin²(x))
               cos⁻¹(cos(x)) = cos⁻¹(√1 - sin²(x))
                                 x = 0

4. -tan²(x) + sec²(x) = 1
               -1               -1
      tan²(x) - sec²(x) = -1
                    tan²(x) = -1 + sec²
                  √tan²(x) = √(-1 + sec²(x))
                     tan(x) = √(-1 + sec²(x))
            tan⁻¹(tan(x)) = tan⁻¹(√(-1 + sec²(x))
                             x = 0
5 0
3 years ago
Four friends were born on consecutive years. The sum of their ages is 62. What is the age of the youngest friend?
Yuri [45]
<span>Four friends were born on consecutive years.
The sum of their ages is 62. Let's find the age of the youngest friend:
</span><span>Formula:
4x + 6 = 62
=> First is to Subtract 6 from both sides 4x = 56
Then next thing to do is to divide 4 from both sides:
=> x = 14 14 + 14 + 1 + 14 + 2 + 14 + 3 = 62
 62 = 62
 Thus the youngest age is 14</span>
7 0
3 years ago
9/3y-12=1/4y-4 solve for y
Mama L [17]
The answer would be y=32/11
3 0
4 years ago
Read 2 more answers
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