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Marrrta [24]
2 years ago
8

The enrollment at East Valley High School over a six-year period is displayed in the scatterplot.

Mathematics
2 answers:
Savatey [412]2 years ago
8 0

Answer:

Option D is correct.

y = \frac{81}{2}x-\frac{160,069}{2}

Step-by-step explanation:

The equation of line of best-fit for this scatter plot is given by:

y=mx+b

where, m is the slope and b is the y-intercept.

As per the statement:

The enrollment at East Valley High School over a six-year period is displayed in the scatter-plot.  

Student Enrollment at East Valley High School

Here, x represents the number of years and y represents the number of students.

Enter the values of x into one list and the values for y into the second list.    

You can see the graph of the scatter plot as shown below in the attachment.

we get, the equation of line is:

y = 40.57x-80182

or we can write this as:

y = \frac{81}{2}x-\frac{160,069}{2}

Therefore, the  equation of the line of best-fit for this scatter plot is:

y = \frac{81}{2}x-\frac{160,069}{2}

Ierofanga [76]2 years ago
4 0
D 100% corect took my test $$$$$$$$$$$$$$
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mihalych1998 [28]

Answer:

  Slope = 7/4

Step-by-step explanation:

You are given coordinate values and a formula that tells you what to do with them. All you need to do is put the values in the formula and do the arithmetic.

<h3>Points</h3>

You are given points (2, -3) and (6, 4). The slope formula refers to the two points as (x1, y1) and (x2, y2). It does not matter which is which.

If we use the points in the same order they are given, then we can see that ...

  • x1 = 2
  • y1 = -3
  • x2 = 6
  • y2 = 4

<h3>Formula</h3>

Using these values in the given formula, we find the slope to be ...

  m=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{4-(-3)}{6-2}=\dfrac{7}{4}

The slope of the line through the given points is 7/4.

4 0
1 year ago
Help me with 20 please
Murrr4er [49]

24%------360(24% is 360m)

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8 0
3 years ago
4x-3y=2<br> 3x=5y=16<br> solve using substitution method
vodomira [7]

\left\{\begin{array}{ccc}4x-3y=2&|\text{add 3y to both sides}\\3x+5y=16\end{array}\right\\\left\{\begin{array}{ccc}4x=3y+2&|\text{divide both sides by 4}\\3x+5y=16\end{array}\right\\\left\{\begin{array}{ccc}x=0.75y+0.5&(*)\\3x+5y=16\end{array}\right\\\\\text{substitute}\ (*)\ \text{to the second equation}\\\\3(0.75y+0.5)+5y=16\qquad\text{use distributive property}\\\\(3)(0.75x)+(3)(0.5)+5y=16\\\\2.25y+1.5+5y=16\qquad\text{subtract 1.5 from both sides}\\\\7.25y=14.5\qquad\text{divide both sides by 7.25}

\boxed{y=2}\\\\\text{substitute the value of y to}\ (*):\\\\x=0.75(2)+0.5\\\\x=1.5+0.5\\\\\boxed{x=2}\\\\Answer:\ x=2\ and\ y=2\to(2,\ 2)

7 0
2 years ago
Which is greater -9 or -4 explain
Alexxandr [17]

Answer:

-4

Step-by-step explanation:

-4 is closer to the 0

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3 0
2 years ago
Read 2 more answers
Please help me out :P
Veseljchak [2.6K]

cos θ = \frac{-4\sqrt{65} }{65}, sin θ = \frac{-7\sqrt{65} }{65}, cot  θ  = 4/7, sec  θ = \frac{-\sqrt{65} }{4}, cosec  θ  = \frac{-\sqrt{65} }{7}

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = \sqrt{7^{2} + 4^{2} } = \sqrt{49+16} = \sqrt{65}

sin θ = opposite/ hyp = \frac{7}{\sqrt{65} }

Rationalize, \frac{7}{\sqrt{65} } x \frac{\sqrt{65} }{\sqrt{65} } = \frac{7\sqrt{65} }{65}

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - \frac{7\sqrt{65} }{65}

cos   θ  = adj/hyp = \frac{4}{\sqrt{65} }

By rationalizing and knowing that cos  θ  is negative, cos θ  = -\frac{-4\sqrt{65} }{65}

cot θ  = 1/tan θ  = 1/7/4 = 4/7

sec θ  = 1/cos θ  = 1/\frac{4}{\sqrt{65} } = -\frac{-\sqrt{65} }{4}

cosec θ  = 1/sin θ  = 1/\frac{\sqrt{65} }{7} = \frac{-\sqrt{65} }{7}

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0
1 year ago
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