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Marrrta [24]
2 years ago
8

The enrollment at East Valley High School over a six-year period is displayed in the scatterplot.

Mathematics
2 answers:
Savatey [412]2 years ago
8 0

Answer:

Option D is correct.

y = \frac{81}{2}x-\frac{160,069}{2}

Step-by-step explanation:

The equation of line of best-fit for this scatter plot is given by:

y=mx+b

where, m is the slope and b is the y-intercept.

As per the statement:

The enrollment at East Valley High School over a six-year period is displayed in the scatter-plot.  

Student Enrollment at East Valley High School

Here, x represents the number of years and y represents the number of students.

Enter the values of x into one list and the values for y into the second list.    

You can see the graph of the scatter plot as shown below in the attachment.

we get, the equation of line is:

y = 40.57x-80182

or we can write this as:

y = \frac{81}{2}x-\frac{160,069}{2}

Therefore, the  equation of the line of best-fit for this scatter plot is:

y = \frac{81}{2}x-\frac{160,069}{2}

Ierofanga [76]2 years ago
4 0
D 100% corect took my test $$$$$$$$$$$$$$
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You invested 11000 in in 2st fund and 9000 in 2nd fund

<h3><u>Solution:</u></h3>

Given that, You invested money in two funds.  

Last year, the first fund paid a dividend of 8% and the second a dividend of 5%, and you received a total of $1330.  

This year, the first fund paid a 12% dividend and the second only 2%, and you received a total of $1500.

Let the amount in Fund I be $x and amount in Fund II be $ y

Then, for last year ⇒ 0.08x+0.05y=1330 ----- eqn (1)  

And for this year ⇒ 0.12x+0.02y=1500 ------- eqn (2)  

Multiply (1) by 2 ⇒ 0.16 x + 0.1 y = 2660  

Multiply (2) by 5 ⇒ 0.6 x + 0.1 y = 7500

Subtract the two equations  

(2) ⇒ 0.6x + 0.1y = 7500

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Now, from eqn (2)  

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0.02y = 1500 – 1320  

0.02y = 180  

y = 9000

Hence, he invested 11000 in in 2st fund and 9000 in 2nd fund

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