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Talja [164]
3 years ago
14

How do you solve problems involving sequence? Discuss the mathematics concepts and principles applied when solving problems invo

lving sequence
Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
7 0

Step-by-step explanation:

Sequence is defined as arrangement f numbers in a specific or defined pattern. Sequence are categorized into

1) Arithmetic

2) Geometric

Arithmetic sequence are characterized by their common difference while Geometric sequence are characterized by their common ratio.

Given a sequance of numbers say;

T1, T2, T3...

The first term "a" of the sequence is T1

Common difference d = T2-T1 =T3-T2

Common ratio = T2/T1 = T3/T2

The formula for calculating nth term of an Arithmetic sequence is expressed as;

Tn = a+(n-1)d

a is the first term

n is the number of terms

d is the common difference

The nth term of a Geometric sequence is expressed as;

Tn = ar^{n-1}

r is the common ratio

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If f(x) = 3 – 2x and 1/x+5, what is the value of (f/g)(8)? –169 –1 13 104
Basile [38]
I'm assuming that this is the complete question.
If f(x) = 3 – 2x and g(x)=1/(x+5), what is the value of (f/g)(8)? a) –169       b) –1      c) 13     d) 104
x = 8
f(x) = 3 -2xf(8) = 3 - 2(8) = 3 - 16 = -13
g(x) = 1/(x+5)g(8) = 1/(8+5) = 1/13
(f/g)(8)f(8)/g(8) = -13/ (1/13) = -13 * 13 = -169  Choice A :)
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4 years ago
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kotykmax [81]

Answer:

A and B

Step-by-step explanation:

8 0
2 years ago
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Can any plz help me how to do "a"
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5 0
3 years ago
Solve triangle ABC. (If an answer does not exist, enter DNE. Round your answers to one decimal place. Below, enter your answers
OleMash [197]

Answer:

∠A1 = 27.4°, ∠A2 = 56.6°, ∠C1 =104.6°, ∠C2=75.4°, a1 = 79.9 and a2 = 144.9

Step-by-step explanation:

From Sine rule

\frac{a}{sinA}=\frac{b}{sinB} = \frac{c}{sinC}

∴ b / sinB = c / sinC

From the question,

b = 129, c = 168 and ∠B = 48°

∴ 129 / sin48° = 168 / sinC

Then, sinC = (168×sin48)/129

sinC = 0.9678

C = sin⁻¹(0.9678)

C = 75.42

∠C2=75.4°

and

∴∠C1 = 180° - 75.4°

∠C1 =104.6°

For ∠A

∠A1 = 180° - (104.6°+48°) [sum of angles in a triangle]

∠A1 = 27.4°

and

∠A2 = 180° - (75.4° + 48°)

∠A2 = 180° - (123.4°)

∠A2 = 56.6°

For side a

a1/sinA1 = b/sinB

a1/ sin27.4° = 129/sin48

a1 = (129×sin27.4°)/sin48

a1 = 79.8845

a1 = 79.9

and

a2/sinA2 = b / sinB

a2/ sin56.6° = 129/sin48

a2 = (129×sin56.6°)/sin48

a2 = 144.9184

a2 = 144.9

Hence,

∠A1 = 27.4°, ∠A2 = 56.6°, ∠C1 =104.6°, ∠C2=75.4°, a1 = 79.9 and a2 = 144.9

4 0
3 years ago
Let f(x)=-2-7 and g(x)= -4x+6. Find (f*g)(-5)
Masja [62]
If (-5) = x then the anwser should be
-234

5 0
3 years ago
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