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aalyn [17]
3 years ago
9

Can any plz help me how to do "a"

Mathematics
1 answer:
Gemiola [76]3 years ago
5 0
A) 1,3,5,7,9,11,13,15
There r 8 odd number rooms
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Find the quotient. ​
finlep [7]

Answer:11 to the 15th power :)

Step-by-step explanation:

you subtract the lower number from the higher number and in this case since the higher number is on top, the answer goes on top which means it’s positive

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Two pounds of dried cranberries cost $5.04, 3 pounds of dried cranberries cost $7.56, and 7 pounds of dried cranberries cost $17
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Answer:

y = 2.52x

y = cost, x = pounds of cranberries.

each pound costs 2.52

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5.04/2 = 2.52

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Step-by-step explanation:

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3 years ago
Solve y=f(x) for x. Then find the input when the output is -3.
DochEvi [55]

Answer:

Please check the explanation

Step-by-step explanation:

Given the function

f\left(x\right)\:=\:\left(x-5\right)^3-1

Given that the output = -3

i.e. y = -3

now substituting the value y=-3 and solve for x to determine the input 'x'

\:\:y=\:\left(x-5\right)^3-1

-3\:=\:\left(x-5\right)^3-1\:\:\:

switch sides

\left(x-5\right)^3-1=-3

Add 1 to both sides

\left(x-5\right)^3-1+1=-3+1

\left(x-5\right)^3=-2

\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}

Thus, the input values are:

x=-\sqrt[3]{2}+5,\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}-i\frac{\sqrt[3]{2}\sqrt{3}}{2},\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}+i\frac{\sqrt[3]{2}\sqrt{3}}{2}

And the real input is:

x=-\sqrt[3]{2}+5

  • x=3.74
4 0
3 years ago
Half a number decreased by two
Savatey [412]
X = a number
1/2(x) - 2
Or
x/2 - 2
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3 years ago
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