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arsen [322]
2 years ago
6

The hypotenuse is NOT:

Mathematics
1 answer:
Natali5045456 [20]2 years ago
4 0

Answer:

NOT found in obtuse triangles

Step-by-step explanation:

you only talk about hypotenuse, adjacent, and opposite in right triangle

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Pleaseee help asap!!! marking brainiest!!!
yan [13]

Answer:

B

Step-by-step explanation:

We can see that both functions are decreasing in [0,4]

  • f    868⇒ 103
  • g   800⇒0
  • 868-103 =765

f decreased with 765 against 800 for g

g decreased faster

3 0
3 years ago
You score a 95% on your math quiz. The quiz was out of 60 points. How many points did you get​
Vladimir [108]

Answer:

57

Step-by-step explanation:

95% of 60 is 57.

4 0
2 years ago
Read 2 more answers
5.2.14. For the negative binomial pdf p (k; p, r) = k+r−1 (1 − p)kpr, find the maximum likelihood k estimator for p if r is know
Volgvan

Answer:

\hat p = \frac{r}{\bar x +r}

Step-by-step explanation:

A negative binomial random variable "is the number X of repeated trials to produce r successes in a negative binomial experiment. The probability distribution of a negative binomial random variable is called a negative binomial distribution, this distribution is known as the Pascal distribution".

And the probability mass function is given by:

P(X=x) = (x+r-1 C k)p^r (1-p)^{x}

Where r represent the number successes after the k failures and p is the probability of a success on any given trial.

Solution to the problem

For this case the likehoof function is given by:

L(\theta , x_i) = \prod_{i=1}^n f(\theta ,x_i)

If we replace the mass function we got:

L(p, x_i) = \prod_{i=1}^n (x_i +r-1 C k) p^r (1-p)^{x_i}

When we take the derivate of the likehood function we got:

l(p,x_i) = \sum_{i=1}^n [log (x_i +r-1 C k) + r log(p) + x_i log(1-p)]

And in order to estimate the likehood estimator for p we need to take the derivate from the last expression and we got:

\frac{dl(p,x_i)}{dp} = \sum_{i=1}^n \frac{r}{p} -\frac{x_i}{1-p}

And we can separete the sum and we got:

\frac{dl(p,x_i)}{dp} = \sum_{i=1}^n \frac{r}{p} -\sum_{i=1}^n \frac{x_i}{1-p}

Now we need to find the critical point setting equal to zero this derivate and we got:

\frac{dl(p,x_i)}{dp} = \sum_{i=1}^n \frac{r}{p} -\sum_{i=1}^n \frac{x_i}{1-p}=0

\sum_{i=1}^n \frac{r}{p} =\sum_{i=1}^n \frac{x_i}{1-p}

For the left and right part of the expression we just have this using the properties for a sum and taking in count that p is a fixed value:

\frac{nr}{p}= \frac{\sum_{i=1}^n x_i}{1-p}

Now we need to solve the value of \hat p from the last equation like this:

nr(1-p) = p \sum_{i=1}^n x_i

nr -nrp =p \sum_{i=1}^n x_i

p \sum_{i=1}^n x_i +nrp = nr

p[\sum_{i=1}^n x_i +nr]= nr

And if we solve for \hat p we got:

\hat p = \frac{nr}{\sum_{i=1}^n x_i +nr}

And if we divide numerator and denominator by n we got:

\hat p = \frac{r}{\bar x +r}

Since \bar x = \frac{\sum_{i=1}^n x_i}{n}

4 0
3 years ago
Alexander placed four straws on his table.
Diano4ka-milaya [45]

Answer:D (straws 2 and 4)

Step-by-step explanation:

The answer is D becuase those two straws intersect at point and create 90° angle

6 0
3 years ago
What is the value of b<br> 2b + 8 − 5b + 3 = −13 + 8b − 5
Yuri [45]

Answer:

See below.

Step-by-step explanation:

2b + 8 − 5b + 3 = −13 + 8b − 5

Reorder like terms.

2b-5b+8+3=8b-13-5

Combine those like terms. Then solve.

-3b+11=8b-18

      -11       -11

-3b=8b-29

-8b -8b

-11b=-29

/-11    /-11

b=2.64

-hope it helps

3 0
2 years ago
Read 2 more answers
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