Question

What is the distance between (-2,2) and (2,-1) on coordinate plane

Answer 1

Answer:

$d=\sqrt(x2-x1)^{2} + (y2-y1)^{2}$

Step-by-step explanation:

1- Identify the x and  the y

x1= -2

x2=2

y1= 2

y2= -1

2-

2- solve the equation:

d=$\sqrt$(2-(-2))$^{2}$  + ((-1)-2)$^{2}$

d= $\sqrt$(4)$^{2}$        + (-3)$^{2}$

= $\sqrt$16        + 9

= $\sqrt$25

d=5 answer