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2 years ago

What is the distance between (-2,2) and (2,-1) on coordinate plane

Mathematics

1 answer:

lawyer [7]2 years ago

6 0

Answer:

$d=\sqrt(x2-x1)^{2} + (y2-y1)^{2}$

Step-by-step explanation:

1- Identify the x and the y

x1= -2

x2=2

y1= 2

y2= -1

2- solve the equation:

d= $\sqrt\$ (2-(-2)) $^{2}$ + ((-1)-2) $^{2}$

d= $\sqrt$ (4) $^{2}$ + (-3) $^{2}$

= $\sqrt$ 16 + 9

= $\sqrt$ 25

d=5 answer

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2 years ago

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2 years ago

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Answer:

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2 years ago

PLEASE HELP ME

stiv31 [10]

Since it's a right triangle you can use the Pythagorean theorem or Trig (Soh Cah Toa).

I'll just use the Pythagorean theorem : a² + b² = c²
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9² + x² = 18²
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3 years ago

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Galina-37 [17]

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Step-by-step explanation:

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