Answer:
x^2 -2x + 1
Step-by-step explanation:
Think of a quadratic equation as
ax^2 + bx + c
x^2 -2x +
Comparing the two equations
a = 1 , b = -2, c = ?
c becomes the missing part
Divide b by 2
-2/2 = -1
square the result
-1^2
= 1 this is what to add to get a perfect square
x^2 -2x + 1
(x - 1)^2
Step-by-step explanation:
x2-8x-3x+24=0
x(x-8) 3(x+8)
(x-8)(x+8)
x-8=0 or x+8=0
x=8. x= -8
Answer:
(a) There are asymptotes at x=3/2 and x=-1/3
Step-by-step explanation:
The denominator zeros can be found by factoring:
f(x) = (x +1)/((2x -3)(3x +1))
Neither of the denominator factors is cancelled by the numerator factor, so each represents a vertical asyptote, not a function hole.
The asymptotes are at the values of x where the denominator is zero:
2x -3 = 0 ⇒ x = 3/2
3x +1 = 0 ⇒ x = -1/3
Answer:
(x) =
Step-by-step explanation:
let y = f(x), then rearrange making x the subject
y =
x + 4 ( subtract 4 from both sides )
y - 4 =
x ( multiply both sides by 5 to clear the fraction )
5y - 20 = x
Change y back into terms of x with x =
(x) , then
(x) = 5x - 20
Answer:
144
Step-by-step explanation:
12*12 =144