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vichka [17]
3 years ago
15

Thomas can process a pile of paperwork in 4 hours less time than Frank. Together they can process the pile in 2.1 hours. How lon

g would it take Frank to do the job alone?
Mathematics
1 answer:
stiks02 [169]3 years ago
8 0

Answer:

F = 7 hours

Step-by-step explanation:

Let the time taken by Frank to work alone be F.

Translating the word problem into an algebraic equation;

Thomas alone takes (F - 4) hours.

Combine time = 2.1 hours

Their individual work rate expressed in piles per hour are;

Frank = 1/F

Thomas = 1/(F - 4)

Combined rate = 1/F + 1/(F - 4)

Simplifying the equation, we have;

Combined rate = (F - 4 + F)/F(F - 4)

Combined rate = (2F - 4)/F(F - 4)

Combined rate = (2F - 4)/(F²- 4F)

Now to find the time taken when they work together is;

(2F - 4)/(F²- 4F) = 1/2.1

Cross-multiplying, we have;

2.1*(2F - 4) = F² - 4F

4.2F - 8.4 = F² - 4F

Rearranging the equation, we have;

F² - 4.2F - 4F + 8.4 = 0

F² - 8.2F + 8.4 = 0

Solving the quadratic equation by factorization;

Factors = -7 and -1.2

F² - 7F - 1.2F + 8.4 = 0

F(F - 7) - 1.2(F - 7) = 0

(F - 7)(F - 1.2) = 0

Therefore, F = 7 or 1.2 hours

The time taken by Frank alone would be 7 hours.

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516 cm squared

Step-by-step explanation:

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Hannah sells computers. The amount of her monthly sales for the first half of the year are listed below:
yulyashka [42]

Answer:

Mean = $16,500

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Step-by-step explanation:

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14000+18000+13000+19000+21000+14000 / 6  Cancel the common factors

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we get rid of the 2 and the 6 by factoring them out.  so we now get

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13000, 14000, 14000, 18000, 19000, 21000

So we will take 14000 and 18000 and add them together then divide by 2.

14000 + 18000 = 32000/2 = $16,000

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