Answer:
Angle MJK = 64°
Step-by-step explanation:
In ∆MJL & ∆LJK,
JL= JL ...(common side)
Angle JML = Angle JKL ....( each 90°)
MJ = JK ....( Both measures 7)
Hence, by SAS criteria, ∆ MJL = ∆ LJk
.°. by C.P.C.T , ∠MJL = ∠LJK = 32°
Also,
∠MJK = ∠MJL+∠LJK
∠MJK = 32°+32°
<h2>∠MJK = 64°</h2>
Given:
The figure of a quadrilateral ABCD.
To find:
The supplement of angle ABC.
Solution:
We know that, two angles are called supplementary angles if their sum is 180 degrees.


So,
is not a supplement of
.


So,
is not a supplement of
.



So,
is a supplement of
.
In the same way
.
So,
is not a supplement of
.
Therefore, the correct option is C.
The complete question in the attached figure
we have that
250°----------> belong to the third quadrant
if 2pi radians-------------> 360°
X-------------------------> 250°
X=250*2pi/360------------> 1.39 pi radians
then
<span>the radian measure of the central angle is 1.39pi
</span>
hence
the answer is
the option C) pi to 1.39pi radians