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Degger [83]
3 years ago
5

The battery life for Bruhier's cell phone is longer when he has fewer apps running. When only one app is running, the battery wi

ll last for
16 hours. When four apps are running, the battery will only last for 4 hours.
This situation represents
variation.
The constant of variation, k, is equal to
If eight apps are running, Bruhler's battery will last for 4 hours
Mathematics
2 answers:
trapecia [35]3 years ago
8 0

Answer:inverse, 16, 2

Step-by-step explanation:

andrew11 [14]3 years ago
3 0

Answer:

inverse, 16, 4

Step-by-step explanation:

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a plane figure with at least three straight sides and angles, and typically five or more.

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Write out the first few terms of the series Summation from n equals 0 to infinity (StartFraction 2 Over 3 Superscript n EndFract
anyanavicka [17]

Answer:

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = 15/8

Step-by-step explanation:

The sum you are trying to understand is this.

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n}

Remember that in general when you have a geometric series  

\sum\limits_{n = 0}^{\infty} a*r^n you have that

\sum\limits_{n = 0}^{\infty} a*r^n = \frac{a}{1-r}      and that equality is true as long as     |r| < 1.

Therefore here we have

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{3*5} \big)^n = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n        and   \big|\frac{-1}{15} \big| = \frac{1}{15} < 1

Therefore we can use the formula and

\sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n =  \frac{2}{1-(-1/15)} = \frac{2}{1+1/15} = 30/16  = 15/8

5 0
3 years ago
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