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QveST [7]
3 years ago
13

In southern California, a growing number of individuals pursuing teaching credentials are choosing paid internships over traditi

onal student teaching programs. A group of eleven candidates for five local teaching positions consisted of six who had enrolled in paid internships and five who enrolled in traditional student teaching programs. All eleven candidates appear to be equally qualified, so five are randomly selected to fill the open positions. Let Y be the number of internship trained candidates who are hired. (a) Does Y have a binomial or hypergeometric distribution
Mathematics
1 answer:
Irina18 [472]3 years ago
6 0

Answer:

Candidates are chosen without replacement, thus trials are dependent, meaning that Y has a hypergeometric distribution.

Step-by-step explanation:

Difference between hypergeometric and binomial distributions:

In the hypergeometric distribution, trials are dependent of other trials, while in the binomial distribution, they are independent. This can be examplified that in the hypergeometric distribution, the candidates are chosen from a set without replacement, while in the binomial distribution they are chosen with replacement.

In this question:

Candidates are chosen without replacement, thus trials are dependent, meaning that Y has a hypergeometric distribution.

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Translate ƒ(x) = |x| so that it's translated up by 5 units and vertically stretched by a factor of 3. What's the new function g(
zavuch27 [327]

Given:

The parent absolute function is

f(x)=|x|

To find:

The new function if the parent function is translated up by 5 units and vertically stretched by a factor of 3.

Solution:

The translation is defined as

g(x)=kf(x+a)+b                .... (1)

Where, k is stretch factor, a is horizontal shift and b is vertical shift.

If 0<k<1, then the graph compressed vertically by factor k and if k>1, then the graph stretch vertically by factor k.

If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.

If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.

Parent function is translated up by 5 units. So, b=5

It is vertically stretched by a factor of 3. So, k=3.

There is no horizontal shift. So, a=0.

Now, putting k=3, a=0 and b=5 in (1), we get

g(x)=3f(x+0)+5

g(x)=3f(x)+5

g(x)=3|x|+5       [\because f(x)=|x|]

Therefore, the correct option is D.

5 0
3 years ago
Find the cos A and tan B to four decimal places. URGENT
Nikolay [14]

cos A is 0.8511 and tan B is 1.6

Step-by-step explanation:

Find the 3rd length or the hypotenuse.

<u>Pythagoras theorem</u>

hypotenuse^{2} = adjacent^{2} + opposite^{2}

hypotenuse^{2} = 8^{2} + 5^{2}

hypotenuse^{2} = 64 + 25

hypotenuse = \sqrt{89}

hypotenuse = 9.4

a) Cos A

<u>Data:</u>

Adjacent = 8

Hypotenuse = 9.4

<u>Formula:</u>

Cos (Angle) = \frac{adjacent}{hypotenuse}

Cos A =  \frac{8}{9.4}

Cos A = 0.8511

A = cos^{-1} (0.8511)

A = 31.7°

b) Tan B

<u>Data: </u>

Opposite = 8

Adjacent = 5

<u>Formula:</u>

Tan (Angle) = \frac{opposite}{adjacent}

Tan B = \frac{8}{5}

Tan B = 1.6

B =  cos^{-1} (1.6)

B = 58°

Therefore, cos A is 0.8511 and tan B is 1.6.

Keyword: cos, tan

Learn more about cos at

  • brainly.com/question/5013374
  • brainly.com/question/9532142

#LearnwithBrainly

3 0
3 years ago
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