Find the radius of a circle in which an inscribed square has a side of 8 inches.
1 answer:
Answer:
Step-by-step explanation:
The square is in the circle, so the diameter is the diagonal line of the square. This divides the square into two right triangles.
Two sides of the right triangle equal 8. This qualifies it as a special right triangle. This triangle has two sides that = x (in this case 8) and the hypotenuse is .
Substitute 8 in for x.
is the diameter, so we divide in half to get the radius =
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<u>ANSWER</u>
<u>EXPLANATION</u>
This very simple to do.
First locate the entry in in matrix A. That is the entry in the intersection of the fourth row and first column of matrix A. This entry is
.
Then multiply by the scalar which is 2 to get,
.
Next we locate the entry in in matrix B also. Which is
. We multiply by the scalar of
to get,
.
We now add these two corresponding entries to obtain,
See diagram
Answer
The answer and procedures of the exercise are attached in the following archives.
Step-by-step explanation:
You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.
