Find the radius of a circle in which an inscribed square has a side of 8 inches.
1 answer:
Answer:
Step-by-step explanation:
The square is in the circle, so the diameter is the diagonal line of the square. This divides the square into two right triangles.
Two sides of the right triangle equal 8. This qualifies it as a special right triangle. This triangle has two sides that = x (in this case 8) and the hypotenuse is .
Substitute 8 in for x.
is the diameter, so we divide in half to get the radius =
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<h3>I'll teach you how to solve 8x² = 15 - 14x</h3>
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8x² = 15 - 14x
Add 14x to both sides:
8x^2 +14x =15-14x+14x
Simplify:
8x^2 +14x =15
Subtract 15 from both sides:
8x^2+14x-15 = 15-15
SImplify:
8x^2+14x-15 = 0
Solve with the quadratic formula:
x= = 3/4
x= = -5/2
The solutions to the quadratic formula are:
x= 3/4, x=-5/2
Your Answer Is x= 3/4, x=-5/2
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