Find the radius of a circle in which an inscribed square has a side of 8 inches.
1 answer:
Answer:
Step-by-step explanation:
The square is in the circle, so the diameter is the diagonal line of the square. This divides the square into two right triangles.
Two sides of the right triangle equal 8. This qualifies it as a special right triangle. This triangle has two sides that = x (in this case 8) and the hypotenuse is .
Substitute 8 in for x.
is the diameter, so we divide in half to get the radius =
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Answer:
The equation in the slope-intercept form will be:
y = 1/4x - 7
Step-by-step explanation:
Given the points
- (-4.-8)
- (-8, -9)
We know that the slope-intercept of line equation is
where m is the slope and b is the y-intercept
substituting m = 1/4 and the point (-4, -8) to find the y-intercept 'b'
y = mx+b
-8 = 1/4(-4)+b
-8 = -1 + b
b = -8+1
b = -7
so the y-intercept = b = -7
substituting m = 1/4 and b = -7 in the slope-intercept form of line equation
y = mx+b
y = 1/4x + (-7)
y = 1/4x - 7
Thus, the the equation in slope-intercept form will be:
y = 1/4x - 7
