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3 years ago

Which of the following is an open statement?

1 answer:

6 0

I think the last one because a open statement contains at least one blank that becomes true or false when it’s filled in if you fill x with 4 you will get 3(4) 3*4=13 so if that blank was filled in with 4 it would be true

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The graphs of linear functions f and g are shown on the grid.

ziro4ka [17]

Answer: B

Step-by-step explanation:

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3 years ago

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Steven conjectures that for |x|>5, it is true that x^3>125. Is his conjecture correct? Why or why not?

levacccp [35]

Answer:

yes

Step-by-step explanation:

it is correct because, since x>5, anything relating x and 5 together will always put x greater than 5.

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3 years ago

you spend $90 on books and movies. You pay $12 per book and $15 pr movie. YOu buy 3 more books than movies. How many of each ite

Leya [2.2K]

You bought 5 books for $60 and 2 movies for $30

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3 years ago

Yoshi is 5% taller today than she was one year ago. Her current height is 168 cm. How tall was she one year ago

NemiM [27]

155.6 CM
I divided 168 by 100 to find 1% then i got 1.68cm then I times that by 5 to find 5% which was 8.4cm. Finally I subtracted 168 and 8.4 to get 155.6 CM
I hope that helped :)

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3 years ago

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which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1

lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. $y=\sec x$

B. $y= \tan x$

C. $y= \cot x$

D. $y= \csc x$

Answer:

A. $y=\sec x$

D. $y=\csc x$

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: $y=\sec x$

We know that, the $\sec x=\frac{1}{\cos x}$

The range of $\cos x$ is from -1 to 1 given as [-1, 1]. So,

$|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the secant function as:

$\sec x\leq -1\ or\ \sec x\geq 1\\$

Therefore, the range of $y=\sec x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

Choice B: $y= \tan x$

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: $y= \cot x$

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: $y=\csc x$

We know that, the $\csc x=\frac{1}{\sin x}$

The range of $\sin x$ is from -1 to 1 given as [-1, 1]. So,

$|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

$\csc x\leq -1\ or\ \csc x\geq 1\\$

Therefore, the range of $y=\csc x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

6 0

3 years ago