All categories

3 years ago

Which of the following is an open statement?

1 answer:

6 0

I think the last one because a open statement contains at least one blank that becomes true or false when it’s filled in if you fill x with 4 you will get 3(4) 3*4=13 so if that blank was filled in with 4 it would be true

You might be interested in

Which is smaller: 5 nanometers or 50 micrometers

lina2011 [118]

5 nanometers is smaller

8 0

3 years ago

Read 2 more answers

I'll give brainliest!!!!

Anna [14]

Answer: B

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Is F=((x,y) | x+y=10 a function or a relation

asambeis [7]

that is a function man

7 0

3 years ago

A small companys net income for the first six months of the year was $76,500 and for the last six months it was $100,000. What i

Alex_Xolod [135]

Divide until you get one moth alone then multiply then simplify if you don't know how to simplify please pm me.

6 0

3 years ago

A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex

Olenka [21]

Answer:

The 90% confidence interval that estimate the true proportion of students who receive financial aid is

$0.533 < p < 0.64$

$n = 1789$

Step-by-step explanation:

Considering question a

From the question we are told that

The sample size is n = 200

The number of student that receives financial aid is $k = 118$

Generally the sample proportion is

$\^ p = \frac{k}{n}$

=> $\^ p = \frac{118}{200}$

=> $\^ p = 0.59$

From the question we are told the confidence level is 90% , hence the level of significance is

$\alpha = (100 - 90 ) \%$

=> $\alpha = 0.10$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }$

=> $E = 1.645 * \sqrt{\frac{0.59 (1- 0.59)}{200} }$

=> $E = 0.057$

Generally 90% confidence interval is mathematically represented as

$\^ p -E < p < \^ p +E$

=> $0.533 < p < 0.64$

Considering question b

From the question we are told that

The margin of error is E = 0.03

From the question we are told the confidence level is 99% , hence the level of significance is

$\alpha = (100 - 99 ) \%$

=> $\alpha = 0.01$

Generally from the normal distribution table the critical value of is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the sample size is mathematically represented as

$[\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )$

=> $n = [\frac{2.58}{0.03} ]^2 * 0.59 (1 - 0.59 )$

=> $n = 1789$

8 0

3 years ago