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olga2289 [7]
2 years ago
13

What is the scale factor of the dilation

Mathematics
2 answers:
Fittoniya [83]2 years ago
8 0
The scale factor would be 2, since the image is 2 times bigger than the pre-image.

Hope this helps! :) I did this last year, so this is the correct answer! ;)
Darya [45]2 years ago
5 0

Answer:  The answer is 2.

Step-by-step explanation:  We are given to find the scale factor for the dilation of a triangle shown in the figure.

The triangle ABC is dilated to form the triangle A'B'C'.

To find the scale factor, we need to divide the length of one side of the dilated triangle A'B'C' by the length of the corresponding side of the original triangle ABC.

From the figure, we note that

AB = 5 units  and  A'B' = 10 units.

Therefore, the scale factor will be

S_f=\dfrac{A'B'}{AB}=\dfrac{10}{5}=2.

Thus, the answer is 2.

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gtnhenbr [62]

Answer:

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Step-by-step explanation:

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6 0
2 years ago
Which fraction is equivalent to 16/20 ?A.8/100 <br> B.6/10<br> C.48/60<br> D.20/24
denis23 [38]

Answer:

Step-by-step explanation:

16/20 = 48/60

960 = 960

Answer is C

3 0
2 years ago
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The vertices of triangle rst are r(–1,–2), s(2,–1), and t(4,2). If δjkl ∼ δrst and the length of kl is units , what is the lengt
NemiM [27]

Answer:

3.16 units

Step-by-step explanation:

It has been given that the triangles JKL and the triangle RST are congruent.

That implies that, the length of the side JK, KL, and JL is equivalent to the length of the sides RS, ST, and RT respectively.

Now, to find the length of JK we need to find the length of the side RS. The coordinates of the points R and S are (-1,-2) and (2,-1).

The length of the side RS is equal to the distance between point R and S.

RS =\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

= \sqrt{(2-(-1))^2+(-1-(-(-2))^2}

=\sqrt{3^2+(-1+2)^2}

=\sqrt{9+1}=\sqrt{10}=3.16

Now that we have the length of the side RS, and the triangles JKL and RST are congruent therefore, the length of the side JK is 3.16 units.

7 0
3 years ago
Read 2 more answers
A bank loaned out $21,500 , part of it at the rate of 11% annual interest, and the rest at 10% annual interest. The total intere
Luda [366]

Answer:

The loaned amount at 11 % is $ 19,000

The loaned amount at 10 % is $ 2,500

Step-by-step explanation:

Given as :

The total loan amount = $21,500

The total interest earn = $2,340.00

The rate of interest are 11 %  and 10 %

Let The loan amount at 11 % rate = $P

and The loan amount at 10 % rate = $21,500 - $P

Let The loan took for 1 year

Now,<u> From Simple Interest method </u>

Simple Interest = \dfrac{\textrm Principal\times \textrm Rate\times \textrm Time}{100}

SI_1 = \dfrac{P_1\times R_1\times \textrm Time}{100}

Or, SI_1 = \dfrac{P\times 11\times \textrm 1}{100}

Similarly

SI_2 = \dfrac{21,500 - P\times 10\times \textrm 1}{100}

∵  SI_1 +  SI_2 =  $2,340

Or, \dfrac{P\times 11\times \textrm 1}{100} + \dfrac{21,500 - P\times 10\times \textrm 1}{100} = $2,340

Or, 11 P - 10 P + 215000 = 234000

Or, P = 234000 - 215000

∴ P = $ 19,000

And $21,500 - $ 19,000 = $ 2,500

Hence The loaned amount at 11 % is $ 19,000

And     The loaned amount at 10 % is $ 2,500    Answer

8 0
3 years ago
What is the solution of 3x + y = 9 and 3x − 5y = 15?
Alinara [238K]
3x+y=9 ....(1)
3x-5y=15. ......(2)
-[3x-5y=15]
=> 3x+ y = 9
-3x+5y=-15
..........................
0 +6y=-6
so,y=-1
3x+(-1)=9
3x=10
x=10/3
4 0
3 years ago
Read 2 more answers
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