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Lelu [443]
3 years ago
7

Find the slope of the line graphed below

Mathematics
2 answers:
Rainbow [258]3 years ago
8 0
Using the form rise/run your graph has a slope of 1/2 with a y-intercept of 1
irina1246 [14]3 years ago
7 0

Answer:

Up one over two = m<rise/run = 1/2

Step-by-step explanation:

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The cost of renting a table at the flea market is based on a fixed price per day plus an initial registration fee. If it costs $
Simora [160]

Answer:

c = 15d + 30

Step-by-step explanation:

Hey there!

This can be represented by an equation of a line, where the number of days is our x-values(d), and the price is our y-values(c).

The price for one day ($45) and the price for 4 days($90) are specific points on that line.

The points are (1, 45) and (4, 90).

We can first find the slope of the line:

  • As the price rises 45, the days increase by 3
  • Slope = rise/run
  • Slope = 45/3
  • Slope = 15

Now we can find the base price, by plugging the slope and a point into the equation y = mx + b.

Solve for b:

  • y = mx + b
  • 45 = 15(1) + b
  • 45 = 15 + b
  • 30 = b

The base price (b) is 30.

The equation is \text{\boxed{c = 15d + 30}}

6 0
2 years ago
Write each product using an exponent: example 6x6==
swat32
Since 6x6 equals 36, then 6² would be the exponent because 6² is the same as 6x6
3 0
3 years ago
One number is 6 greater than another. the product of the number is 55. find the numbers
Basile [38]
Here's how to do this problem:

6+ x= 55
-6       -6
x=49
5 0
3 years ago
At Southside Middle School, 20% of the students play an instrument. There are 305 students. How many students play an instrument
stellarik [79]
61 students

.2x305= 61
4 0
3 years ago
Read 2 more answers
The radius of a right circular cone is increasing at a rate of 1.4 in/s while its height is decreasing at a rate of 2.3 in/s. At
Angelina_Jolie [31]

Answer:

The volume is changing at a rate given by:

\frac{dV}{dt} =19559.56\,\,\frac{in^3}{s}

Step-by-step explanation:

Let's recall the formula for the volume of acone, since it is the rate of the cone changing what we need to answer:

Volume of cone = \frac{1}{3} B\,*\,H

where B is the area of the base (a circle of radius R) which equals = \pi\,R^2

and where H stands for the cone's height.

We apply the derivative over time operator (\frac{d}{dt}) on both sides of the volume equation, making sure that we apply the rule for the derivative of a product:

V=\frac{1}{3} B\,*\,H\\\\V= \frac{1}{3} \pi\,R^2\,H\\\frac{dV}{dt} =\frac{\pi}{3}\,( \frac{d(R^2)}{dt} H+R^2\,\frac{dH}{dt} )\\\frac{dV}{dt} =\frac{\pi}{3}\,( 2\,R\,\frac{dR}{dt}\, H+R^2\,\frac{dH}{dt} )\\\frac{dV}{dt} =\frac{\pi}{3}\,( 2\,(110\,in)(1.4\,\frac{in}{s} )\,(151\,in)+(110\.in)^2\,(-2.3)\frac{in}{s} )\\\frac{dV}{dt} =19559.56\,\,\frac{in^3}{s}

8 0
3 years ago
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