Answer:
Step-by-step explanation:
It is a function. Every x has only 1 y associated with it. You cannot find an exception to this rule.
Stated another more common way: if you take a ruler and lay it flat on the graph so that the ruler is parallel to the y axis, you will find the ruler will go through only one y for every x. That's called the vertical line test.
Answer:
D. x=5
The answer is x=4.50 then it is rounded off to 5. So, the answer is 5.
Step-by-step explanation:
Find the domain of the inequality:
Rearrange terms to the left side of the equation:
Divide both sides of the inequality by the coefficient of the variable:
=> 
The domain of the inequality is:
Convert logarithm to exponential form:
Calculate the power:
Rearrange terms to the left side of the equation:
Calculate:
Divide both sides of the equation by the coefficient of the variable:
=> 
=>
Round the number: 
Answer: 
=> 
Read to know more about log equation:
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The correct option is D for the placement of regular polygon and the rhombus.
<h3>What is defined as the
regular polygon?</h3>
- A polygon is a two-dimensional enclosed image created by connecting three or more straight lines.
- A rhombus is a special parallelogram because it meets the definition of a parallelogram, which is a quadrilateral to two pairs of parallel sides.
- A polygon is made up of three parts:
- Sides: A side is a line segment that connects two vertices.
- Vertices: A vertex is the point where two sides meet.
- Interior and exterior angles An interior angle is an angle formed by joining the sides of a polygon within its enclosed surface.
As, all the given figures comes under the regular polygon, all are placed in the left circle.
But the three diagram in white, orange and blue colour are regular polygon along with rhombus.
Thus, all three are placed in the intersection of the both circle of the vein diagram.
To know more about the regular polygon, here
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A combination is an unordered arrangement of r distinct objects in a set of n objects. To find the number of permutations, we use the following equation:
n!/((n-r)!r!)
In this case, there could be 0, 1, 2, 3, 4, or all 5 cards discarded. There is only one possible combination each for 0 or 5 cards being discarded (either none of them or all of them). We will be the above equation to find the number of combination s for 1, 2, 3, and 4 discarded cards.
5!/((5-1)!1!) = 5!/(4!*1!) = (5*4*3*2*1)/(4*3*2*1*1) = 5
5!/((5-2)!2!) = 5!/(3!2!) = (5*4*3*2*1)/(3*2*1*2*1) = 10
5!/((5-3)!3!) = 5!/(2!3!) = (5*4*3*2*1)/(2*1*3*2*1) = 10
5!/((5-4)!4!) = 5!/(1!4!) = (5*4*3*2*1)/(1*4*3*2*1) = 5
Notice that discarding 1 or discarding 4 have the same number of combinations, as do discarding 2 or 3. This is being they are inverses of each other. That is, if we discard 2 cards there will be 3 left, or if we discard 3 there will be 2 left.
Now we add together the combinations
1 + 5 + 10 + 10 + 5 + 1 = 32 choices combinations to discard.
The answer is 32.
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Note: There is also an equation for permutations which is:
n!/(n-r)!
Notice it is very similar to combinations. The only difference is that a permutation is an ORDERED arrangement while a combination is UNORDERED.
We used combinations rather than permutations because the order of the cards does not matter in this case. For example, we could discard the ace of spades followed by the jack of diamonds, or we could discard the jack or diamonds followed by the ace of spades. These two instances are the same combination of cards but a different permutation. We do not care about the order.
I hope this helps! If you have any questions, let me know :)
Answer:
(-1/2, 1)
Step-by-step explanation:
I just used the midpoint formula, and plugged in the points. I hope this helps!
=(x^2+x^1 /2 , y^2+y^1 /2)
=(-2+1 /2 , -5+3 /2)
=(-1/2, 1)