Match the number with its opposite. (4 points)

There are 5 pens in a container on your desk. Among them, 3 will write well but 2 have defective ink cartridges. You will select

Norma-Jean [14]

Answer:

Kindly check explanation

Step-by-step explanation:

Total Number of pens = 5

Number of defective pens = 2

Number of non-defective pens = 3

A.) number of defective pens selected :

X : {0, 1, 2}

It is possible that no defective pen will be selected ; 1 defective will be chosen or both pens are defective.

2.)

Defective as Success (since selecting a defective pen is the point of interest.

3.)

Since selection is done without replacement

Probability of success per selection is different for each selection ;

Number of defective = 2

Number of observations = 5

P(success on first selection) = 2/5

P(success on second selection) = 1/4

Hence, X is not well approximated by a binomial random variable.

4.) if selection is done with replacement ; then then the probability of success per selection will be the Same for each selection made. Hence, X will be well approximated by a binomial Random variable.

5.) If sampling is done without replacement, then the the hypergeometric function will be a more effective approximation.

7 0

3 years ago

1. If h(x) = 4x - 2, then which of the following is the solution to h(x) = 3 ?

luda_lava [24]

Answer:

10

Step-by-step explanation:

h(x)=4x-2 h(x)=3

h(3)=4(3)-2 substitute

h(3)=12-2 multiply

=10 subtract

8 0

2 years ago

Ramona is 39 years old, and she owns her car, which she uses to drive to work. Her collision deductible is $500, and she does no

laiz [17]

Answer:

Ramona’s annual premium is $1725.

Step-by-step explanation:

($690) X 2 X 1.25 = $1725.

7 0

3 years ago

What type of number is<br> -4 pi

kobusy [5.1K]

-4 pi is an irrational number

5 0

3 years ago

Marie is getting married tomorrow, at an outdoor ceremony in the desert. In recent years, it has rained only 5 days each year. U

kogti [31]

Answer:

11.11% probability that it will rain on the day of Marie's wedding, given the weatherman forecasts rain

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

$P(B|A) = \frac{P(B)*P(A|B)}{P(A)}$

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Forecast of rain.

Event B: Raining.

In recent years, it has rained only 5 days each year.

A year has 365 days. So

$P(B) = \frac{5}{365} = 0.0137$

When it actually rains, the weatherman correctly forecasts rain 90% of the time.

This means that $P(A|B) = 0.9$

Probability of forecast of rain:

90% of 0.0137(forecast and rains)

10% of 1 - 0.0137 = 0.9863(forecast, but does not rain)

$P(A) = 0.0137*0.9 + 0.9863*0.1 = 0.11096$

What is the probability that it will rain on the day of Marie's wedding, given the weatherman forecasts rain

$P(B|A) = \frac{0.0137*0.9}{0.11096} = 0.1111$

11.11% probability that it will rain on the day of Marie's wedding, given the weatherman forecasts rain

3 0

3 years ago