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oksian1 [2.3K]
3 years ago
11

Ramona is 39 years old, and she owns her car, which she uses to drive to work. Her collision deductible is $500, and she does no

t have comprehensive coverage. If her car's safety rating is 17, what is her annual premium?
Mathematics
1 answer:
laiz [17]3 years ago
7 0

Answer:

Ramona’s annual premium is $1725.

Step-by-step explanation:

($690) X 2 X 1.25 = $1725.

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The coefficient of xy in the product of (4x2 + 2y) and (3x + y2) is
dedylja [7]
(4x2 + 2y)(3x+y^2)

= 12x^3 + 4x^2y^2 + 6xy + 2y^3

coefficient of xy is ----> 6
8 0
3 years ago
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What is the value of x?
Helga [31]

2x+20=3x-30

x=50

2x+20=3x-30

x=50

2x+20=3x-30

x=50

2x+20=3x-30

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7 0
3 years ago
Which expression is equivalent to...? Screenshots attached. Please help! Thank you.
Studentka2010 [4]

Answer:

4x^{3} y^{2} (\sqrt[3]{4 x y})

Step-by-step explanation:

Another complex expression, let's simplify it step by step...

We'll start by re-writing 256 as 4^4

\sqrt[3]{256 x^{10} y^{7} } = \sqrt[3]{4^{4} x^{10} y^{7} }

Then we'll extract the 4 from the cubic root.  We will then subtract 3 from the exponent (4) to get to a simple 4 inside, and a 4 outside.

\sqrt[3]{4^{4} x^{10} y^{7} } = 4 \sqrt[3]{4 x^{10} y^{7} }

Now, we have x^10, so if we divide the exponent by the root factor, we get 10/3 = 3 1/3, which means we will extract x^9 that will become x^3 outside and x will remain inside.

4 \sqrt[3]{4 x^{10} y^{7} } = 4x^{3} \sqrt[3]{4 x y^{7} }

For the y's we have y^7 inside the cubic root, that means the true exponent is y^(7/3)... so we can extract y^2 and 1 y will remain inside.

4x^{3} \sqrt[3]{4 x y^{7} } = 4x^{3} y^{2} \sqrt[3]{4 x y}

The answer is then:

4x^{3} y^{2} \sqrt[3]{4 x y} = 4x^{3} y^{2} (\sqrt[3]{4 x y})

4 0
3 years ago
What is the relationship between sin(90 degrees) and sin(-90 degrees)
Volgvan

Answer:

sin(90\°)=-sin(-90\°)

Step-by-step explanation:

we know that

sin(90\°)=1

sin(-90\°)=-1

therefore

sin(90\°)=-sin(-90\°)

4 0
3 years ago
What is the sum of the arithmetic series below?
Irina-Kira [14]
Hello : 
the common ratio is r = -95-(-100)=5
the general terme is : un= u1+(n-1)r
un = -100 +(n-1)(5)
un =-100 +5n-5
un = 5n-105
The last term is : 100
un =100
5n-105 = 100
5n =205
n = 41 (Number of terms)
The last term is : u 41
<span>the sum is : S= (41/2)(-100+100)=0</span>
5 0
3 years ago
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