CD would be double AB, which is 148
The mistakes that were made regarding the transformation are:
- He applied the reflection to the pre-image first.
- He used an incorrect angle of rotation around point P
<h3>How to illustrate the information?</h3>
It should be noted that a transformation simply means the changing of the position of an object
In this case, the transformation is incorrect as he applied the reflection to the pre-image first and used an incorrect angle of rotation around point P.
Learn more about transformation on:
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7 is 71+7/3+78
8 is 60x2x2
Exponentially growth.
Let’s say one person starts with the flu. After the first day, there are suddenly
1 x 2 = 4 people sick
And the rest of the days just explode in magnitude:
Day 2: 1 x 2 x 2 = 8 people sick
Day 3: 1 x 2 x 2 x 2 = 16 people sick
Day 4: 1 x 2 x 2 x 2 x 2 = 32 people sick
Etc.
You can rewrite all that repeated multiplication as *exponents*, which is why we call it exponential growth.
Day 1: 1 x 2^1 = 4
Day 2: 1 x 2^2 = 8
Day 3: 1 x 2^3 = 16
And after n days, 1 x 2^n - or just 2^n - people would be sick.
The system is:
i) <span>2x – 3y – 2z = 4
ii) </span><span>x + 3y + 2z = –7
</span>iii) <span>–4x – 4y – 2z = 10
the last equation can be simplified, by dividing by -2,
thus we have:
</span>i) 2x – 3y – 2z = 4
ii) x + 3y + 2z = –7
iii) 2x +2y +z = -5
The procedure to solve the system is as follows:
first use any pairs of 2 equations (for example i and ii, i and iii) and equalize them by using one of the variables:
i) 2x – 3y – 2z = 4
iii) 2x +2y +z = -5
2x can be written as 3y+2z+4 from the first equation, and -2y-z-5 from the third equation.
Equalize:
3y+2z+4=-2y-z-5, group common terms:
5y+3z=-9
similarly, using i and ii, eliminate x:
i) 2x – 3y – 2z = 4
ii) x + 3y + 2z = –7
multiply the second equation by 2:
i) 2x – 3y – 2z = 4
ii) 2x + 6y + 4z = –14
thus 2x=3y+2z+4 from i and 2x=-6y-4z-14 from ii:
3y+2z+4=-6y-4z-14
9y+6z=-18
So we get 2 equations with variables y and z:
a) 5y+3z=-9
b) 9y+6z=-18
now the aim of the method is clear: We eliminate one of the variables, creating a system of 2 linear equations with 2 variables, which we can solve by any of the standard methods.
Let's use elimination method, multiply the equation a by -2:
a) -10y-6z=18
b) 9y+6z=-18
------------------------ add the equations:
-10y+9y-6z+6z=18-18
-y=0
y=0,
thus :
9y+6z=-18
0+6z=-18
z=-3
Finally to find x, use any of the equations i, ii or iii:
<span>2x – 3y – 2z = 4
</span>
<span>2x – 3*0 – 2(-3) = 4
2x+6=4
2x=-2
x=-1
Solution: (x, y, z) = (-1, 0, -3 )
Remark: it is always a good attitude to check the answer, because often calculations mistakes can be made:
check by substituting x=-1, y=0, z=-3 in each of the 3 equations and see that for these numbers the equalities hold.</span>
