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KonstantinChe [14]
2 years ago
9

X + 3y = 1 5x +6y = 14

Mathematics
2 answers:
marshall27 [118]2 years ago
4 0

Answer:

1. X = 1 - 3y

2. -5/6x + 7/3

Those are the answers to the problems

rusak2 [61]2 years ago
3 0
(x,y) = (4,-1)

x + 3y = 1 subtract 5 from both sides you get -5x -15y =-5

now sum it up
-5x -15y =-5
5x +6y = 14
you get -9y = 9
divide both sides by -9

you get y=-1

NOW substitute y for x + 3 times (-1)= 1

solve for x and get x=4

therefore your answer is (4,-1)

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A diver was 40 feet below the surface of the water. A fisherman was casting off a dock right above the diver that was 12 feet ab
Nesterboy [21]

Answer:

The answer is D.

Step-by-step explanation:

It is D because they cannot be negative feet away and if the fisherman is 12ft above water and the diver is 40ft below than 40 + 12 = 52. Hope this helps.

5 0
2 years ago
8) Find the endpoint Cif M is the midpoint of segment CD and M (2, 4) and D (5,7)
Elenna [48]

Answer:

8. c. (-1, -1)

9. a. (-6, -1)

b. True

Step-by-step Explanation:

8. Given the midpoint M(2, 4), and one endpoint D(5, 7) of segment CD, the coordinate pair of the other endpoint C, can be calculated as follows:

let D(5, 7) = (x_2, y_2)

C(?, ?) = (x_1, y_1)

M(2, 4) = (\frac{x_1 + 5}{2}, \frac{y_1 + 7}{2})

Rewrite the equation to find the coordinates of C

2 = \frac{x_1 + 5}{2} and 4 = \frac{y_1 + 7}{2}

Solve for each:

2 = \frac{x_1 + 5}{2}

2*2 = \frac{x_1 + 5}{2}*2

4 = x_1 + 5

4 - 5 = x_1 + 5 - 5

-1 = x_1

x_1 = -1

4 = \frac{y_1 + 7}{2}

4*2 = \frac{y_1 + 7}{2}*2

8 = y_1 + 7

8 - 7 = y_1 + 7 - 7

1 = y_1

y_1 = 1

Coordinates of endpoint C is (-1, 1)

9. a.Given segment AB, with midpoint M(-4, -5), and endpoint A(-2, -9), find endpoint B as follows:

let A(-2, -9) = (x_2, y_2)

B(?, ?) = (x_1, y_1)

M(-4, -5) = (\frac{x_1 + (-2)}{2}, \frac{y_1 + (-9)}{2})

-4 = \frac{x_1 - 2}{2} and -5 = \frac{y_1 - 9}{2}

Solve for each:

-4 = \frac{x_1 - 2}{2}

-4*2 = \frac{x_1 - 2}{2}*2

-8 = x_1 - 2

-8 + 2 = x_1 - 2 + 2

-6 = x_1

x_1 = -6

-5 = \frac{y_1 - 9}{2}

-5*2 = \frac{y_1 - 9}{2}*2

-10 = y_1 - 9

-10 + 9 = y_1 - 9 + 9

-1 = y_1

y_1 = -1

Coordinates of endpoint B is (-6, -1)

b. The midpoint of a segment, is the middle of the segment. It divides the segment into two equal parts. The answer is TRUE.

4 0
3 years ago
3) If the population of the United States increased to 420 million and the number of
shutvik [7]

Answer:

About 965517 Americans.

7 0
2 years ago
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Type this equation in standard form. 8y + 4 = -3x
Nitella [24]
Y = -3/8x+ -2/4 the answer
5 0
2 years ago
During halftime of a basketball ​game, a sling shot launches​ T-shirts at the crowd. A​ T-shirt is launched from a height of 4 f
Sonbull [250]

Answer:

(a) The time the T-shirt takes to maximum height is 2 seconds

(b) The maximum height is 68 ft

(c) The range of the function that models the height of the T-shirt over time given above is 4 + 64\cdot t - 16 \cdot  t^{2}

Step-by-step explanation:

Here, we note that the general equation representing the height of the T-shirt as a function of time is

h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

Where:

h = Height reached by T-shirt

t = Time of flight

u = Initial velocity = 64 ft/s

g = Acceleration due to gravity (negative because upward against gravity) = 32 ft/s²

h₁ = Initial height of T-shirt = 4 ft

(a) The maximum height can be found from the time to maximum height given as

v = u - gt

Where:

u = Initial velocity = 64 ft/s

v = Final upward velocity at maximum height = 0 m/s

g = 32 ft/s²

Therefore,

0 = 64 - 32·t

32·t = 64 and

t = 64/32 = 2 seconds

(b) Therefore, maximum height is then

h = 4 + 64\times 2 - \frac{1}{2} \times 32  \times  2^{2}

∴ h = 68 ft

The T-shirt is then caught 41 ft above the court on its way down

(c) The range of the function that models the height of the T-shirt over time given above is derived as

h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

With u = 64 ft/s

g = 32 ft/s² and

h₁ = 4 ft

The equation becomes

h =4 + 64\cdot t - \frac{1}{2} \times 32  \cdot  t^{2} = 4 + 64\cdot t - 16 \cdot  t^{2}.

6 0
3 years ago
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