Explanation
Let's first graph the elements:
Using the distance formula we get:
Answer:
Quadrant III
Step-by-step explanation:
The attached picture shows graph of 4 such linear functions with the conditions given in the problem. ALL of them DO NOT pass through Quadrant III.
The graphs shown are of the functions:
<em>So, any linear function of the form 
with 
and 
does not pass through Quadrant III. Answer choice 3 is correct.</em>
Answer:
6 roots
Step-by-step explanation:
f(x)=3x^6+2x^5+x4-2x^3
The number of roots is determined by the degree of the polynomial. They may be real or complex.
Since this is a 6th degree polynomial, it will have 6 roots
f(x)=3x^6+2x^5+x4-2x^3
(x - 2)² + (y - 6)² = 4
You can be certain about one thing just by looking at the equation (2, 6) is the center, so, obviously the circle isnt going through this point
Since the radius is 2 if we don't move from y = 6 we have points in (0, 6) and (4, 6)
So alternative b.
To be more certain just subs the point in the x and y, if its equal, it pass through
(x - 2)² + (y - 6)² = 4
To point (4, 6)
(4 - 2)² + (6 - 6)² = 4
(2²) + 0² = 4
4 = 4
Thats right
Answer:
c = 10/n + 2
Step-by-step explanation:
