Answer:
The 99% confidence interval estimate of the percentage of girls born is (86.04%, 93.96%). Considering the actual percentage of girls born is close to 50%, the percentage increased considerably with this method, which means that it appears effective.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of
.
In the study 380 babies were born, and 342 of them were girls.
This means that
99% confidence level
So
, z is the value of Z that has a p-value of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:

As percentages:
0.8604*100% = 86.04%.
0.9396*100% = 93.96%.
The 99% confidence interval estimate of the percentage of girls born is (86.04%, 93.96%). Considering the actual percentage of girls born is close to 50%, the percentage increased considerably with this method, which means that it appears effective.
Answer: 7
Step-by-step explanation:
Answer:
2x
Step-by-step explanation:
Combine the négative and get -5x+7x then combine to get 2x.
Answer:
13.A) y= 4/3 x+1
D) all real numbers
Step-by-step explanation:

<span>4x•2-12x=7
Subtract 12x from 4x
-8x*2=7
Divide 2 on both sides
-8x=3.5
Divide both sides by -8
Final Answer: x= -0.4375</span>